
#1
Apr112, 08:54 AM

P: 307

Simple question I am confused on. If I have a tensor [latex]M^{\alpha\beta\gamma}[/latex] that is totally antisymmetric in its indices then is it the case that M changes sign under the exchange of any two indices? And as a followup, a totally symmetric tensor has no sign changes on any pair exchange of indices?
Thanks, Kevin 



#2
Apr112, 09:09 AM

Sci Advisor
HW Helper
PF Gold
P: 4,768

What is your definition of a tensor, and of a totally antisymmetric tensor (resp. totally symmetric tensor)?




#3
Apr112, 09:16 AM

P: 635





#4
Apr112, 09:41 AM

P: 307

Meaning of totally antisymmetric tensor
Damn I think I figured out my problem. I was going off Carroll's definition/discussion of (anti) symmetry (Spacetime and Geometry) which implies that an exchange of a pair of indices in a totally antisymmetric tensor yields a sign change. This is fine I realize now, what is not fine is the following.
I was looking at [latex]\partial_{\alpha}F_{\beta\gamma}[/latex]. I know that [latex]\partial_{\[\alpha}F_{\beta\gamma\]}=0[/latex] and I then INCORRECTLY assumed that [latex]\partial_{\alpha}F_{\beta\gamma}[/latex] was totally symmetric which was leading me into errors....argh....noob mistake. 


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