What does the mass represent in the Schwarzschild metric for vacuum solutions?

In summary, the Schwarzschild metric is a solution to the vacuum Einstein equations for a spherically symmetric, non-rotating, and uncharged mass. The mass term in the metric represents the total mass-energy of the central object, and the solution is only valid outside the massive object. The singularity in the solution is a special case and indicates that the energy momentum tensor is zero.
  • #1
physicslover8
1
0
Sorry if I am asking a too trivial question! I am having a confusion regarding the following-The solution to Einstein equation in vacuum is given by the Schwarzschild metric. However, what does the mass represent in the metric in Schwarzschild coordinate? Whose mass is it and how does it enter although we are looking for vacuum solutions, meaning T_{ab}=0
 
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  • #2
The Schwarzschild metric is one particular solution to the vacuum Einstein equations for the particular case of one spherically symmetric, stationary (non-rotating), uncharged mass. There are other solutions to the vacuum field equations (e.g. Kerr metric). The mass term is a boundary value representing the total mass-energy of the central object.
 
  • #3
To be more precise, the Schwarzschild solution is a solution of empty space "up to one point". You could see it as the solution of which the energy momentum tensor is given by

[tex]
T_{\mu\nu} = \rho \delta_{\mu}^0 \delta_{\nu}^0 \delta^4 (r)
[/tex]

where rho is some mass density. With other words: if [itex] r \neq 0 [/itex] then [itex]T_{\mu\nu} = 0 [/itex], whereas for r=0 one has that [itex]T_{\mu\nu} \rightarrow \infty[/itex] indicating a singularity.
 
  • #4
Or rather, the Schwarzschild solution is valid outside any massive, spherically symmetric object. A good analogy would be to the electric field outside a ball of charge. Outside the ball, there is no charge density, but there is an electric field from the ball. Similarly, outside a massive, spherically symmetric object, there are still effects from gravity, but the stress-energy tensor is zero.
 
  • #5
haushofer said:
To be more precise, the Schwarzschild solution is a solution of empty space "up to one point" ... indicating a singularity.
No.

As Muphrid says
Muphrid said:
the Schwarzschild solution is valid outside any massive, spherically symmetric object.
the Schwarzschild solution is applicable for all for spherically symmetric massive bodies; the the singularity is only a special case
 

Related to What does the mass represent in the Schwarzschild metric for vacuum solutions?

1. What is the Vacuum Einstein Equation?

The Vacuum Einstein Equation, also known as the Einstein field equations, is a set of ten partial differential equations that describe the curvature of spacetime in the absence of any matter or energy. They were developed by Albert Einstein as part of his theory of general relativity.

2. Why is the Vacuum Einstein Equation important?

The Vacuum Einstein Equation is important because it provides a mathematical framework for understanding the fundamental nature of gravity and its effects on the universe. It has been validated through numerous experiments and observations and is considered one of the cornerstones of modern physics.

3. How is the Vacuum Einstein Equation derived?

The Vacuum Einstein Equation is derived from the principle of equivalence, which states that the effects of gravity are indistinguishable from the effects of acceleration. It also incorporates the concept of spacetime curvature and is based on the mathematics of differential geometry.

4. What are the implications of the Vacuum Einstein Equation?

The Vacuum Einstein Equation has several implications, including the prediction of the bending of light around massive objects, the existence of black holes, and the expansion of the universe. It has also been used to successfully explain and predict various phenomena in cosmology, such as the cosmic microwave background radiation.

5. Are there any limitations to the Vacuum Einstein Equation?

While the Vacuum Einstein Equation has been incredibly successful in describing gravity and its effects, it does have limitations. It does not account for the behavior of matter at the quantum level and cannot be reconciled with other theories such as quantum mechanics. This has led to ongoing efforts to develop a unified theory of physics that can incorporate both general relativity and quantum mechanics.

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