Finding parametric equations for the line through the point that is perpendicular to

by coleko
Tags: calculus, physics, vector mechanics
 P: 2 Finding parametric equations for the line through the point that is perpendicular to plane and parallel? What is the difference when finding parametric equations for a line through a point that is perpendicular vs. parallel? Surely there must be some difference but I cannot seem to figure it out. Here is an example Find parametric equations for the line through the point (2,4,6) perpendicular to plane x-y+3x=7 Also find parametric equations for the same line parallel to the same plane... Do you find them both by using r(t)=r+ t*v ?
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P: 12,961
 Quote by coleko Finding parametric equations for the line through the point that is perpendicular to plane and parallel? What is the difference when finding parametric equations for a line through a point that is perpendicular vs. parallel? Surely there must be some difference but I cannot seem to figure it out.
They go in different directions.

Note, there is only one line through a point that is perpendicular to a surface, and an infinite number of possibilities parallel.

 Here is an example Find parametric equations for the line through the point (2,4,6) perpendicular to plane x-y+3x=7 Also find parametric equations for the same line parallel to the same plane... Do you find them both by using r(t)=r+ t*v ?
Some issues with how you phrased that... what you have provided is not the equation of a plane (oh I suppose it could be - it would be 4x-y=7 for any z - so the plane does not intersect the z-axis) ... and "the same line" cannot be parallel. But yes you use the equation of a line both times - but that is not all you do. If r is the point then v must be a vector pointing in some direction: how do you determine that direction?
 P: 2 To find the direction of the vector you would take the coefficients of the plane which would be <1,-1,3> I apologize because the 3x I wrote should really be 3z and the equation should read x-y+3z=7 I also realize that the same line cannot be parallel and perpendicular at the same time I am just questioning my methods on how to figure those out...
 Homework Sci Advisor HW Helper Thanks P: 12,961 Finding parametric equations for the line through the point that is perpendicular to Well, a line through point P at position ##\vec{p}## perpendicular to a plane ##ax+by+cz+d=0## has equation: ##\vec{r}(t)=\vec{p}+\vec{n}t## where ##\vec{n}=(a,b,c)## is the normal to the plane. A line parallel to the same plane would be and of ##\vec{r}(t)=\vec{p}+(a\vec{v}+b\vec{n}\times\vec{v})t## where ##\vec{v}## is any vector in the plane and ##a## and ##b## are arbitrary scalars. See the difference?
 Math Emeritus Sci Advisor Thanks PF Gold P: 39,564 Note that, in three dimensions, there exist a single line through a given point, perpendicular to a given plane but there exist and infinite number of lines through a given point parallel to the given plane.

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