Finding The Distance From A Paraboloid To A Plane.

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Homework Statement



Find the distance from the paraboloid z = X2 + 2Y2 to the plane
2X + 8Y + Z = -8.


Homework Equations



The partial derivatives with respect to X, And Y for the paraboloid.



The Attempt at a Solution



My professor said we need to find the point where the tangent plane of the paraboloid is parallel to the plane. I can take the X, and Y partial derivatives, but then I do not know what to do.
 
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You should know what the normal vector to the plane is by looking at it. You want to find a point on the paraboloid whose normal vector is parallel to that. How would you find a normal vector to the surface at a point (x,y,z)?
 
Oh I just need to move the Z over then take the gradient.
 
Baumer8993 said:
Oh I just need to move the Z over then take the gradient.

Yes, and the simple way to check if two vectors are parallel is to see if one is a multiple of the other.
 
Ok, so now I am stuck at the finding the vectors that are parallel. I know that they can be a multiple of each other. I got the gradient of < 2X, 4y, -1>. I know the normal vector is
<2, 8, 1>.

I set the equations to make:

2X = 2K 4Y = 8K -1 = 1K

K is just a constant. How do I solve these?
 
Baumer8993 said:
Ok, so now I am stuck at the finding the vectors that are parallel. I know that they can be a multiple of each other. I got the gradient of < 2X, 4y, -1>. I know the normal vector is
<2, 8, 1>.

I set the equations to make:

2X = 2K 4Y = 8K -1 = 1K

K is just a constant. How do I solve these?

Good job setting the equations up, but I'm having a hard time figuring out why you can't solve -1=1*K. Take another look at them.
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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