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Circulating a fluid at a very high speed in a spiral pipe 
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#1
Mar2813, 04:11 AM

P: 17

Through a spiral pipe is circulating a fluid with high speed, this will lead to many effects and forces like inertia and gyroscopic effect.
I do not know how to approach the problem in order to find the distribution of forces. In this process of circulating the fluid in spiral pipe will appear lateral forces, or spiral pipe will remain inert because forces cancel each other at all levels? 


#2
Mar2813, 04:20 AM

P: 3,135

Interesting question.
Just looking at the inlet and outlet pipes shows you have mass that enters the system with one velocity and comes out with another velocity (the speed component is the same but the direction component changes). 


#3
Mar2813, 08:07 AM

P: 4,005

I think the force will be just down, like shown in the picture, due to momentum change. It is the same force as with a simple Upiece. To find the distribution go to the rotating rest frame of the water in the turn and consider the pressure gradient caused by the centrifugal force.
For the gyroscopic effect the number of windings does matter, because you have more mass and thus more angular momentum. 


#4
Mar2813, 09:02 AM

P: 17

Circulating a fluid at a very high speed in a spiral pipe
Thank you very much.



#5
Mar2813, 08:38 PM

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P: 5,172

Google Fluid Flow in a Curved Pipe. Such a flow is known to exhibit a secondary flow at each cross section.



#6
Jul2613, 05:35 PM

P: 17

I did a practical experiment to check the distribution of forces and I noticed the appearance of a predominant force which is the result of trajectory change of the fluid.



#7
Jul2713, 11:59 AM

P: 17

Any feedback is appreciated, thank you.



#8
Aug113, 06:17 AM

P: 17

It is assumed that a mass which travels in a closed loop will not generate a linear motion and all forces will cancel each other. Such a system would necessarily violate the law of conservation of momentum.
Imagine that the spiral pipe is a closed loop system, do you think that building a thruster of this kind it is impossible? I think I can demonstrate the opposite. I wait for your opinions. Thank you in advance. 


#9
Aug213, 03:22 AM

P: 4,005

If the fluid goes out at the same velocity as it comes in, there should be no net force on the pipe. But this is not the case in the video: The fluid comes back where it came from, so it changes momentum. There is a reaction force on the float, which interacts with the elastic pipes, causing the swinging. Even if you make the net force zero, you still eventually have a net torque which will cause some movement. There is also possibly a "kick" when you switch the pump on, and the higher pressure straightens the pipes. 


#10
Aug213, 01:35 PM

P: 17

What if the fluid is accelerating?



#11
Aug313, 08:32 PM

P: 14

The coil causes a pressure drop so the inlet pressure will be higher than the outlet pressure. As pressure over an area relates to force there will be an imbalance. Also the friction will allow heat to dissipate along the coil and so an energy transfer happens there. The differential pressure within the pipes will be difficult to quantify as they will want to straighten under pressure, this force may corrupt your test results.
Also the coil you have drawn has a distinct seperation from inlet to outlet but your test apperatus has the pipes close together, you may like to try the test with the pipes as drawn. Acceleration and deacceleration will play a large part in your test as you start and stop the pump. It is a rather elagant test but pipe straightening, P*A forces, heat dissipation and pressure loss make it tricky to deduce meaningful results. Not to mention the pipe shortening due to pressure increase, twisting of the coil as a result and gyroscopic effects causing motion. 


#12
Aug413, 08:04 AM

P: 17

From a simplified perspective I will try to present my point of view on the phenomenon.
Reaction is represented by the force exerted by the pipe walls on the forward path of the fluid, and from there result a change of trajectory equivalent with the distance "d" between the point of entry of the fluid "1" and the output point of the fluid "2". From this change of trajectory of the fluid results a linear force which occurs simultaneously and opposite in direction, according to Newton's third law of motion. 


#13
Aug413, 02:47 PM

P: 4,005




#14
Aug513, 07:26 PM

P: 14

For sure there is a force. 


#15
Aug613, 09:41 AM

P: 1,016




#16
Aug713, 12:34 AM

P: 14




#17
Aug713, 02:00 AM

P: 4,005




#18
Aug1013, 03:40 PM

P: 17

Let's suppose we have a closed loop, as shown in the drawings. From the earlier discussion I concluded that to produce a linear force, acceleration is needed F=m[itex]\ast[/itex]a, but to produce a linear force in one direction, irrespective of the direction of circulation of the fluid in the system, another arrangement is necessary.
From my point of view, irrespective of the direction of fluid circulation, linear force will be generated in one direction and there is no other force to cancel it. 


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