# bolt falls off rocket, find rocket acceleration

by stangeroo
Tags: acceleration, bolt, falls, rocket
 P: 13 A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.70 s later. Find the rockets acceleration. I dont understand how to set up this problem, ive never done something like this , asked some friends and they didnt know how to do it. Any help would be greatly appreciated
 P: 789 Work backwards kind of. If it took 6.7 for the bolt to hit the ground, how high was it? $$d = v_{i}t + \frac{1}{2}at^2$$ vi = 0 a = -32 ft\sec^2 or -9.8 m\sec^2 t = 6.7 s Solve for d. Now, use the same equation and solve for "a" of the rocket. $$d = v_{i}t + \frac{1}{2}at^2$$ d = part a vi = 0 t = 4 Jameson
 Mentor P: 40,261 Do it in two parts, but like this: Part 1: Find the height and speed of the rocket after 4 seconds in terms of the rocket acceleration. Use: $h = 1/2 a t^2$ and $v = a t$ Part 2: Realize that the initial height and speed of the bolt equals the height and speed of the rocket after 4 seconds (which was calculated in part 1). The height of the bolt after it leaves the rocket is: $h = h_0 + v_0t -(g/2)t^2$, using $h_0$ and $v_0$ (in terms of a) from part 1; set h = 0 when t = 6.7 seconds. Solve for a.
P: 13

## bolt falls off rocket, find rocket acceleration

thank you guys

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