Finding q to then raise an object, hoping someone can check this work

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The discussion revolves around a physics problem involving thermodynamics and mechanical work. The initial question asks how high a horse could raise a 217 kg weight in 2.5 minutes, given its ability to heat 11.6 kg of ice water from 273 K to 355 K in 2.5 hours. The calculations provided yield a total energy transfer of approximately 66,270 J, which is then used to determine the height the weight could be raised, resulting in an estimated height of 31.1 meters. While the calculations appear logically sound, there is a mention of confusion regarding the concepts of reversible and irreversible processes, suggesting that the context of the problem might introduce complexities not fully addressed. Overall, the calculations seem valid, but the discussion hints at deeper thermodynamic principles that could complicate the scenario.
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I think I've got this but not 100% sure.

if a horse can heat 11.6kg ice water T=273k to 355K in 2.5 hours how high could it raise a 217kg weight in 2.5 min?

heres what I've done

qp=mcp,sdt=(1.16E4 g)(4.18 J K-1g-1)(82K)=3.976E6 J

(3.976E6 J/2.5hr)(1hr/60min)(2.5min)=6.627E4 J

h=w/mg=6.627E4 J/((217 kg)(9.81m s-2))=31.1m

does this seem legit? we working with all this rev/irr-rev work and transfer and I am getting really mixed up by simple stuff but if p=const then it would be irreversible right?


any suggestions would be great if I am way off track

Thnaks
 
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Looks OK to me (I haven't checked the numbers, just skimmed the logic), but your comment about reversibility/irreversibility makes me wonder if there is not some context to the question which makes it more complicated. But if treated literally as posted - its OK.
 
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