Why Does Reflected Light Experience a Phase Change?

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Reflected light undergoes a 180-degree phase change when it reflects off a medium with a higher index of refraction, while no phase change occurs with a lower index. The Fresnel Relations provide the mathematical foundation for this phenomenon, showing the relationship between incident and reflected electric fields. The phase change can be understood through the equations derived from boundary conditions at the interface of two dielectrics. A specific explanation involves introducing phases and polarization vectors to illustrate how the phase change arises mathematically. The discussion emphasizes the need for clear explanations rather than just references to textbooks.
marlon
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Reflected light will experience a 180 degree phase change when it reflects from a medium of higher index of refraction and no phase change when it reflects from a medium of smaller index. This is very well known. However i am wondering why that is ? Can anyone give me some calculations that actually prove this ?

Thanks

marlon
 
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The "Fresnel Relations" in physics-optics give the reflected E' field as
E'=E_{incident}[(n_1-n_2)/(n_1+n_2)] for normal incidence.
This shows the phase change. The FRs are derived in most junior level EM or optics texts. They follow from the BCs on E and H at the interface of two dielectrics.
The transverse components of each are continuous.
 
The theory of reflection of light is presented in any textbook of optics.I liked and reccomend the bible:M.Born & P.Wolf:"Principles of Optics",any edition,chapter 1,starting with page 36.


Daniel.
 
Guys, if it is so easy why not give me a specific explanation as to why the phase change happens in this particular case ? Dexter, referring to books is useless because i am never going to read that book. I am asking for an explanation and if you cannot give it then don't post just for the sake of posting...Please...

So my question still stands...Anyone who knows the answer ?


regards
marlon
 
Marlon,the equation Meir posted states that,for normal incidence,

E_{reflected}=E_{incident}\frac{n_{1}-n_{2}}{n_{1}+n_{2}}

If n_{1} < n_{2},then E_{reflected}= - k E_{incident} (1)

,where k=:\frac{n_{2}-n_{1}}{n_{1}+n_{2}}>0 (2)

Okay.Now,u write,following (1) & (2)

E_{reflected}=k E_{incident}e^{i\pi} (3)

Is it any clear?Guess not.I introduce the phases and the polarization vectors,okay,then

\vec{E}_{reflected}=\vec{e_{p}}E_{reflected}e^{i\left(\vec{k}_{reflected}\cdot\vec{r}-\omega t\right)} (4)

Using (3),u see where that phase change comes from.

http://scienceworld.wolfram.com/physics/FresnelEquations.html

(For the graph).

Here's a nice course

http://www.ece.rutgers.edu/~orfanidi/ewa/

BTW,it's PHASE.



Daniel.
 
thanks dexter
 
I would like to use a pentaprism with some amount of magnification. The pentaprism will be used to reflect a real image at 90 degrees angle but I also want the reflected image to appear larger. The distance between the prism and the real image is about 70cm. The pentaprism has two reflecting sides (surfaces) with mirrored coating and two refracting sides. I understand that one of the four sides needs to be curved (spherical curvature) to achieve the magnification effect. But which of the...
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