Unveiling the Mystery: How is the Wavefunction of an Electron Revealed?

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The wave functions are the solutions of Schrodinger's equation; if you want to know what the wave function "looks like" you have to set up and solve that equation. The sine wave (and sums of sine waves) are the solution for a free particle such as an electron hanging out in empty space.
 
Thank you. That helped alot
 
On a related note, doing precisely this, calculating electronic wave functions (or similar quantities) of realistic physical systems like molecules and solids is the main subject of a a large branch of physics called "electronic structure theory". Techniques to do this are dealt with in theoretical condensed matter physics and quantum chemistry.
 
PhilDSP said:
There is a recently developed technique which generates an actual picture of the wave function for several electron orbitals of a hydrogen atom using composite snapshots:

http://physics.aps.org/featured-article-pdf/10.1103/PhysRevLett.110.213001

Popular reporting:
http://www.foxnews.com/science/2013/05/28/amazing-first-ever-photograph-inside-hydrogen-atom/

And the comparison between the two should be enough to turn you off from popular reporting forever... No :smile: here.

Note that an "actual picture of the wave function" is not the same thing as a "picture of the actual wave function". This isn't a criticism, as the work in question is still quite fascinatingly cool.
 
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Thread 'Lesser Green's function'
The lesser Green's function is defined as: $$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state. $$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$ First consider the case t <t' Define, $$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$ $$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$ $$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$ ##\ket{\alpha}##...
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