chipotleaway
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Questions about Green's functions for ODEs, jump conditions
I'm having a hard time understanding Green's functions which have been introduced quite early on in the course, and which I think hasn't been well motivated. I can't find any other resource which explains this at this level (have only covered most of 1st order linear DEs before this) so the only thing I have to go by are the lecture slides.
The (one-sided) Green's function is been introduced in the notes as the solution to the DE:
y'+ay=\delta(t-\tau) with y(t_0)=0 and \tau > t_0
the solution being
y(t)=e^{-a(t-\tau)} for t_0 < \tau < t
y(t)=0 for t_0 \leq t < \tau
and this is referred to as the one-sided Green's function.
Two methods for calculating the Green's function are described. First is to obtain the integral solution to the initial value problem
y'+ay=g(t), y(t_0)=0 and just 'read off' the Green's function...but this apparently is not instructive since it gives no insights into what it means.
Second method is to calculate it for
y'+ay=\delta(t-\tau) with y(t_0)=0 and \tau>t_0 in the two domains t_0 \leq t < \tau and t > \tau with the jump condition [y(t)]^{t=t^+}_{t=t^-}=1 which supposedly will give the Green's function.
---
Firstly, what is the point of the Green's function?
What exactly is a 'jump condition' and how do I work with it?
I'm having a hard time understanding Green's functions which have been introduced quite early on in the course, and which I think hasn't been well motivated. I can't find any other resource which explains this at this level (have only covered most of 1st order linear DEs before this) so the only thing I have to go by are the lecture slides.
The (one-sided) Green's function is been introduced in the notes as the solution to the DE:
y'+ay=\delta(t-\tau) with y(t_0)=0 and \tau > t_0
the solution being
y(t)=e^{-a(t-\tau)} for t_0 < \tau < t
y(t)=0 for t_0 \leq t < \tau
and this is referred to as the one-sided Green's function.
Two methods for calculating the Green's function are described. First is to obtain the integral solution to the initial value problem
y'+ay=g(t), y(t_0)=0 and just 'read off' the Green's function...but this apparently is not instructive since it gives no insights into what it means.
Second method is to calculate it for
y'+ay=\delta(t-\tau) with y(t_0)=0 and \tau>t_0 in the two domains t_0 \leq t < \tau and t > \tau with the jump condition [y(t)]^{t=t^+}_{t=t^-}=1 which supposedly will give the Green's function.
---
Firstly, what is the point of the Green's function?
What exactly is a 'jump condition' and how do I work with it?
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