# Massive Vector Boson

by ChrisVer
Tags: boson, massive, vector
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 P: 1,060 Starting from the Lagrangian density: $L= -\frac{1}{4}F_{\mu\nu}F^{\mu\nu} + \frac{m^{2}}{2} B_{\mu}B^{\mu}$ we can derive the E.o.M. for the field $B$ which read: $( \partial^{2} + m^{2}) B^{\mu} - \partial^{\mu} (\partial B) = 0$ In the case of a massive field, I am not sure how I can kill out the partial of B through the field equations.... $\partial B=0$ Does this come as a constraint/boundary condition of minimizing the action? or is there something I cannot see? In most cases they state it's a Lorentz Gauge, however I am not sure how this can be indeed shown...
 P: 1,060 http://www.theory.nipne.ro/~poenaru/...oca_rila06.pdf P.180 , eq 19,20 and the 1st paragraph of p.181 gave the answer... One has to take the derivative of the Equations of Motion $\partial_{\mu}$ and $\partial B$ comes out zero... (unfortunately for me I came out with the wrong EoM missing a minus sign and I couldn't even think of doing it)

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