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trig identity |
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| Sep16-05, 03:26 PM | #1 |
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trig identity
no clue how to start this:
show sin 3x = 3 sin x - 4 sin^3 x |
| Sep16-05, 03:29 PM | #2 |
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How to start this: sin(3x) = sin(2x+x)
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| Sep16-05, 03:38 PM | #3 |
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right so after doing this i get
sin 3x = sin2x(cos x) + (cos2x)(sin x) whats next |
| Sep16-05, 03:52 PM | #4 |
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trig identity
sin(2x)=...?
cos(2x)=...? |
| Sep16-05, 04:21 PM | #5 |
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thanks for the help i got this and the others
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