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derivatives |
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| Oct5-05, 07:23 PM | #1 |
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derivatives
Suppose [tex] f(x) = \frac{(x-3)^{4}}{x^{2}+2x} [/tex]. Find the derivative an determine the values for which it is equal to 0. So [tex] f'(x) = \frac{x^{2}+2x(4(x-3)^{3}) - (x-3)^{4}(2x+2)}{(x^{2}+2x)^{2}} [/tex]. But now how would I go about finding the values for which the derivative equals 0? [tex] f'(x) = \frac{x^{2}+2x(4(x-3)^{3}) (x-3)^{4}(2x+2)}{(x^{2}+2x)^{2}} = 0 [/tex]. Is it possible to factor?
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| Oct5-05, 07:53 PM | #2 |
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For any fraction, let's call it [itex]\frac{A}{B}[/itex], which part will make the whole thing equal to 0? A or B?
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| Oct5-05, 08:08 PM | #3 |
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A
will yeah |
| Oct5-05, 09:08 PM | #4 |
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derivatives |
| Oct6-05, 03:32 AM | #5 |
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Recognitions:
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Your derivative isn't correct yet, make sure you check that first!
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| Oct6-05, 08:16 AM | #6 |
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The derivative is correct, assuming that the missing parentheses BobG mentions is put in correctly!
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