In mathematics, a function f from a set X to a set Y is surjective (also known as onto, or a surjection), if for every element y in the codomain Y of f, there is at least one element x in the domain X of f such that f(x) = y. It is not required that x be unique; the function f may map one or more elements of X to the same element of Y.
The term surjective and the related terms injective and bijective were introduced by Nicolas Bourbaki, a group of mainly French 20th-century mathematicians who, under this pseudonym, wrote a series of books presenting an exposition of modern advanced mathematics, beginning in 1935. The French word sur means over or above, and relates to the fact that the image of the domain of a surjective function completely covers the function's codomain.
Any function induces a surjection by restricting its codomain to the image of its domain. Every surjective function has a right inverse, and every function with a right inverse is necessarily a surjection. The composition of surjective functions is always surjective. Any function can be decomposed into a surjection and an injection.
Homework Statement
i) Show explicitly that any non-injective function with a right inverse has another right inverse
ii) Give an example of a function which has (at least) two distinct left inverses
Homework Equations
i) I don't believe there are any.
ii) "
The Attempt at a Solution...
Reference: http://en.wikipedia.org/wiki/Bijection,_injection_and_surjection
Consider the two sets X & Y connected by a the relation y^2=x^2. (For simplicity we can take X={-2,2} and Y={-2,2}).Then can we call the mapping from X to Y to be surjective?
From the definition of WIKI, the answer...
Hi, I wonder if there are any surjective functions whose range covers all real numbers.
Note that I'm not implying countability, since |R| is uncountable.
For instance,
Sum[rn/n!, {n, 0, m}] : {r, n, m} ∈ R
Thanks for help...
Homework Statement
Here's a nice one. I hope it's correct.
Let p : X --> Y be a closed, continuous and surjective map such that p^-1({y}) is compact for every y in Y. If X is Hausdorff, so is Y.
The Attempt at a Solution
Let y1 and y2 in Y. p^-1({y1}) are then p^-1({y2}) disjoint...
Homework Statement
Let p : X --> Y be a closed, continuous and surjective map. Show that if X is normal, so is Y.
The Attempt at a Solution
I used the following lemma:
X is normal iff given a closed set A and open set U containing A, there is an open set V containing A and whose...
Hello,
is this function surjective?
\Phi : \Re^{+} \diamond \Re \diamond \Re \rightarrow \Re^{3}
(r,\varphi,\theta) \rightarrow (r cos\varphi sin\theta, r sin\varphi sin\theta, r cos\theta)
PS Diamond means X (cross)
I saw this in a book as a Proposition but I think it's an error:
Assume that the (n-by-k) matrix, A, is surjective as a mapping,
A:\mathbb{R}^{k}\rightarrow \mathbb{R}^{n}.
For any y \in \mathbb{R}^{n} , consider the optimization problem
min_{x \in \mathbb{R}^{k}}\left{||x||^2\right}
such...
I saw this in a book as a proposition but I think it's an error:
Assume that the (n-by-k) matrix, A, is surjective as a mapping,
A:R^{k}\rightarrow R^{n}.
For any y \in R^{n} , consider the optimization problem
min_{x \in R^{k}}\left{||x||^2\right}
such that Ax = y.
Then, the following...
Homework Statement
suppose function f : A \to B, g: A \to B, h : B \to C satisfy g \circ f=h \circ f. If is surjective then prove that g=h
Homework Equations
n/a
The Attempt at a Solution
so for any x \in A, gf(x)=hf(x), and for any b \in B there exist a \in A, such that f(b)=a...
Homework Statement
Assume f:A\rightarrowB
g:B\rightarrowC
h=g(f(a))=c
Give a counterexample to the following statement. If h is surjective, then f is surjective.
Homework Equations
Definition ofSurjection: Assume f:A\rightarrowB, For all b in B there is an a in A such that f(a)=b...
Consider the function f: Z -> Z, where f(x) 4x+1 for each x is an element in Z, here the range of F = { ... -8, -5, -2, 1, 4, 7...} is a proper subset of Z, so f is not an onto (surjective) function.
When one examines 3x + 1 = 8, we know x = 7/3, so there is no x in the domain Z with f(x) =...
Homework Statement
let f: R->R be a continuous function
Suppose k>=1 is an integer such that
lim f(x)/x^k = lim f(x)/x^k = 0
x->inf x->-inf
set g(x)= x^k + f(x)
g: R->R
Prove that
(i) if k is odd, then g is surjective
(ii) if k is even, then there is...
Homework Statement
(X,d) a compact metric space, f:X->X cts fn, with
d(f(x),f(y)) >= d(x,y)
for all x, y in X Prove that f is a surjection.The Attempt at a Solution
Let K be the set of points that are not in f(X). It is a union of open balls because X is closed and hence so is f(X).
Choose...
Homework Statement
The following function f is a function from R to R. Determine whether f is injective (one-to-one), surjective (onto), or both. Please give reasons.
Homework Equations
f(x) = (x+1)/(x+2) if x != -2
f(x) = 1 when x = 2
The Attempt at a Solution
f'(x) = 1/(x+2)2...
Question Details:
f(a/b) = 2^a * 3^b where (a/b) is in lowest terms.
Show f is surjective (onto).
Note: f maps positive integers to natural numbers
---
Is it sufficient to say that...
It is onto because for every natural number y there is (a/b) s.t. f(x) = y.
Homework Statement
T ∈ L(V,W). Thread title.
Homework Equations
The Attempt at a Solution
Note that T* is the adjoint operator. But there's one thing that I need to get out of the way before I even start the proof. Now consider <Tv, w>=<v, T*w> w in W, v in V. Now when they say T...
Homework Statement
Let V and W be vector spaces over F, and let T: V -> W be a surjective (onto) linear map. Suppose that {v1, ..., v_m, u1, ... , u_n} is a basis for V such that ker(T) = span({u1, ... , u_n}). Show that {T(v1), ... , T(v_m)} is a basis for W.
Homework Equations
Basic...
Hi, can anyone give me an example of a bounded operator on a Hilbert space that has dense range but is not surjective? (Preferably on a separable Hilbert space)
Im pretty sure such an operator exists since the open mapping theorem requires surjectivity and not just dense range, but its just...
In layman terms otherwise I have trouble understanding
Injective: A function where no element on the domain is many to one.
Surjective: All the elements in the codomain have at least one element from the domain that maps to them.
I'd like to keep it simple so I can play it back to...
For a sirjective function from A--> B, I was just wondering if more than one elements in B can point to the same element in A if the function is surjective.
I'm not sure how i would go about this problem...
Let f: A-> B
(which i know means... f is a function from A to B which also means... that A is the domain and B is the range or image)
Let A0\subsetA and B0\subsetB
a. show that A0\subsetf-1(f(A0)) and the equality hold if f is...
(R:reals)
Let f:R-->R be continuous and satisfy |f(x)-f(y)|>or eq. to k|x-y| for all x, y in R and some k>0. Show that f is surjective.
I can show that f is injective: let f(x) = f(y), hence k|x-y|< or eq. to 0, thus x=y.
I had a suggestion that it might be helpful to show that f has...
Homework Statement
How do I check if my function is surjective?
How do I check if my function is injective?
Suppose my function is a predicate and hence characteristic function of some set. How do I determine such a set?
Homework Equations
Does anyone know to write "The function...
I'm trying to prove that if M,N are normal in G and MN = G, then
G/(M\cap N)\cong G/M \times G/N
In an attempt to use the 1st Isom. Thm, I have a homomorphism from G to G/M x G/N :
g \mapsto (gM, gN)
The kernel is M\cap N, so I just have to show that the function is onto to get the...
Homework Statement
Let f:X\rightarrow~Y and g:Y\rightarrow~Z be surjections. Show that g\circ~f is surjective.
Homework Equations
The Attempt at a Solution
Proof:
Suppose f and g are surjections.
Then (1)\forall~y\in~Y \exists~x\in~X\textnormal{ st. }f(x)=y
And (2)...
I'm a bit stuck here, my question asks me to prove that the product of 2 enumerable sets is indeed enumerable with an argument or a counterexample.
I pretty much have no idea on how to proceed, although i know that the product is enumerable
Hello! I hope I've posted this in the correct section...
I'm a 3rd year undergraduate and we're currently studying Vector Spaces (in QM) and I just don't understand what injective (one-to-one) and surjective (onto) mean? As a result I have no idea what an isomorphism is!
I realize this is...
Homework Statement
I want to show that the homomorphism phi:A(X)->k+k given by taking f(x_1,...,x_n)-> (f(P_1),f(P_2)) is surjective. That is, given any (a,b) in k^2 (with addition and multiplication componentwise) I want to find a polynomial that has the property that f(P_1)=a and f(P_2)=b...
Homework Statement
Show the map (call it phi) from U_n to C*
defined by phi(X) = det(X) for all matrices X in U_n,
is a surjective homomorphism, where
U_n is the subgroup of GL(n,C) consisting of unitary matrices
C* = C\{0} = invertible/nonzero complex numbers
det(.) is the...
how do you prove that a function is surjective ?
i know that surjective means it is an onto function, and (i think) surjective functions have an equal range and codomain?
Hi,
I have no problems with recognising a bijective function -> one-to-one mapping e.g. x^3 is bijective wheras x^2 is not.
But how do you tell weather a function is injective or surjective? I was reading various "math" stuff on this but it has left me only puzzled. Can somebody explain...
[Discrete Math] f: A-->B; surjective? find necessary & sufficient condition.
Ok in practice for my discrete exam, I have the following problem.
Let f : A->B be a function.
a) Show that if f is surjective, then whenever g o f = h o f holds for the functions g,h : B -> C, then g =h.
b)...
Bijections result when the function is surjective and injective.
How do I find a bijection in N and the set of all odd numbers?
f(x) = 2x+1
Do I have to prove that this is one-to-one and onto? Am I on the right track?
Hi, can anyone tell me what a surjective mapping between Hilbertspaces is? That is: what does surjective mean? What about bijective?
I mean what is special about a mapping if it is sujective or bijective?
How can I show the function f:]-\frac{\pi}{2},\frac{\pi}{2}[ \rightarrow R defined by f(x)=tan(x) is surjective?
If the domain was a closed interval I could use the intermediate value theorem, but now?
Thank you.