I'm sorry but what's a relevant equation? a=9.8m/s2 and V1=0m/s and I'm not sure what to put for d and V2 which is what we are solving for. Not sure if that helps?FactChecker said:You should show the relevant equations and what you did with them in your work.
Im sorry I am in grade 12 doing a "University" question. I just wrote down what the question asked me. I have no clue what to do. Sorryvela said:Can you identify what kind of problem this is, e.g., what concepts are relevant? What do you mean by "university acceleration" in the title? You're referring to ##d##, ##v_1##, and ##v_2##. The variable ##d## is defined in the problem statement, but we'd have to guess what you mean by ##v_1## and ##v_2##.
Peter Groppino said:Im sorry I am in grade 12 doing a "University" question. I just wrote down what the question asked me. I have no clue what to do. Sorry
We are given information on both the distance fallen and on the final velocity. From that information [and an assumption of constant acceleration] it is possible to write down an expression for the actual acceleration. That acceleration might not be 9.8 m/s2.Peter Groppino said:I'm sorry but what's a relevant equation? a=9.8m/s2 and V1=0m/s and I'm not sure what to put for d and V2 which is what we are solving for. Not sure if that helps?
The main factors that affect the ball's motion are gravity, air resistance, and the height of the building. Gravity pulls the ball downwards at a constant rate of 9.8 meters per second squared. Air resistance, or the force of air pushing against the ball as it falls, can also impact its motion. The height of the building also plays a role in determining how fast the ball will fall.
The weight of the ball does not impact its descent from the building. In a vacuum, where there is no air resistance, all objects fall at the same rate regardless of their weight. However, in the real world, air resistance can cause lighter objects to fall slower than heavier objects.
No, the material of the building does not affect the ball's motion as long as the building is tall enough to allow the ball to reach its terminal velocity. Terminal velocity is the maximum speed an object can reach while falling, and it is determined by the force of gravity and air resistance.
The higher the building, the faster the ball will be traveling when it reaches the ground. This is because the ball has more time to accelerate due to the force of gravity pulling it downwards. However, once the ball reaches its terminal velocity, increasing the height of the building will not impact its final velocity.
Yes, the ball's motion can be predicted using the equation d=1/2gt^2, where d is the distance traveled, g is the acceleration of gravity (9.8 m/s^2), and t is the time in seconds. This equation allows us to calculate the distance the ball will fall in a given amount of time.