- #1
ramses07
- 11
- 0
1.
A block of mass m = 1.6 kg is dropped from height h = 61 cm (height above the spring, not total height) onto a spring of spring constant k = 1820 N/m (Fig. 8-38). Find the maximum distance the spring is compressed.
K=-U, since all energy is conserved, work would equal zero.
basically kinetic energy is zero, since its starts from zero and ends with zero.
so i this means that the potential energy must equate.
mgh (potential energy from block at H) = (kx^2)/2(potential energy from spring)
so basically the height from the spring is disclosed, but the spring compression isnt.
I tried this first
mg(x+h)=1/2kx^2
1.6kg * 9.8 m/s^2(x+.61cm)=910n/m *x^2
but it gives me an awkward quadratic equation, where the number under the square root would be negative.
I also tried to find to find the kinetic energy right before it touches the spring, and then apply it to the conservation of energy, where 1/2mvf^2=1/2kx^2 but that ddidnt work either, any suggestions?
A block of mass m = 1.6 kg is dropped from height h = 61 cm (height above the spring, not total height) onto a spring of spring constant k = 1820 N/m (Fig. 8-38). Find the maximum distance the spring is compressed.
Homework Equations
K=-U, since all energy is conserved, work would equal zero.
The Attempt at a Solution
basically kinetic energy is zero, since its starts from zero and ends with zero.
so i this means that the potential energy must equate.
mgh (potential energy from block at H) = (kx^2)/2(potential energy from spring)
so basically the height from the spring is disclosed, but the spring compression isnt.
I tried this first
mg(x+h)=1/2kx^2
1.6kg * 9.8 m/s^2(x+.61cm)=910n/m *x^2
but it gives me an awkward quadratic equation, where the number under the square root would be negative.
I also tried to find to find the kinetic energy right before it touches the spring, and then apply it to the conservation of energy, where 1/2mvf^2=1/2kx^2 but that ddidnt work either, any suggestions?