- #1
Nigsia
- 9
- 0
Hello there!
I was doing my Gravitation problems and I found this problem that I'm unable to solve.
I've tried several things, none of them leading to something meaningful. In fact, I know that expression for effective potential is:
[tex]U_{ef}(r)=U(r)+\frac{L}{2r^2}[/tex]
So I imagine I would need to find L fist in order to get the expression for Uef, but I'm not able to remember nor find any kind of formula linking U and L. Would you please help me out?
PS: Once I know how to find L I know how to end it, since:
[tex]\frac{dU_{ef}}{dr} = 0 \Leftrightarrow r = r_0 [/tex]
is the expression of the energy of a circular movement with a radius r0
Thanks in advance.
I was doing my Gravitation problems and I found this problem that I'm unable to solve.
Yukawa's theory for nuclear forces states that the potential energy corresponding to the attraction force produced by a proton and a neutron is:
[tex]U(r) = \frac{k}{r}e^{-\alpha r},\ k<0,\ \alpha > 0[/tex]
From the expression of it's effective potential, find the module of it's angular momentum and it's energy, for which it's possible a circular movement with a radius r0
[tex]U(r) = \frac{k}{r}e^{-\alpha r},\ k<0,\ \alpha > 0[/tex]
From the expression of it's effective potential, find the module of it's angular momentum and it's energy, for which it's possible a circular movement with a radius r0
I've tried several things, none of them leading to something meaningful. In fact, I know that expression for effective potential is:
[tex]U_{ef}(r)=U(r)+\frac{L}{2r^2}[/tex]
So I imagine I would need to find L fist in order to get the expression for Uef, but I'm not able to remember nor find any kind of formula linking U and L. Would you please help me out?
PS: Once I know how to find L I know how to end it, since:
[tex]\frac{dU_{ef}}{dr} = 0 \Leftrightarrow r = r_0 [/tex]
is the expression of the energy of a circular movement with a radius r0
Thanks in advance.