- #1
Dmon1Unlimited
- 1
- 0
I'm looking through my lecture notes, (studying relativistic corrections/perturbation theory using hydrogen), and I seem to have a mind block with one of the equations (the last one from the 3 in the middle).
I know that the kinetic energy and coulomb potential has been subbed in for the operator H0, but I don't understand the rearrangement. Simply multiply both sides by 2*m, then take the coulomb potential to the other side.
The coulomb potential (the e^2 term) on the left hand side is positive, moving it to the right would make it negative, so why is it postive?
I know that the kinetic energy and coulomb potential has been subbed in for the operator H0, but I don't understand the rearrangement. Simply multiply both sides by 2*m, then take the coulomb potential to the other side.
The coulomb potential (the e^2 term) on the left hand side is positive, moving it to the right would make it negative, so why is it postive?