- #1
dukiex3
- 6
- 0
I'm new here, so sorry if I post this incorrectly! =/
I've scanned the lab, and the pictures are below.
Well, the problem statement is in the picture, I guess...
and our givens are that change in X is .35 meters, change in Y is -.91 meters, acceleration of Y = -9.8m/seconds squared, and initial velocity of Y is 0.
change in y (or x) = (vi)(t) + (1/2)(a)(time squared)
velocity final = velocity inital + (a)(t)
velocity final squared= velocity inital squared + (2)(a)(change in x or y)
change in y (or x) = (1/2)(velocity final-velocity initial) (t)
As seen above, we have calculated the time needed for the ball to go from point C into the pan. From this, we then figured out the initial velocity needed for the X component of the ramp. The distance from B-C (though, it has to be greater than zero so that the Y velocity starts at 0) is irrelevant because the velocity for X is always constant. We have figured the acceleration (Sorry I don't have the work for that, my lab partners do.) out by using the equation "velocity final squared= velocity inital squared + (2)(a)(change in x or y)." I am not sure about this acceleration, though. So, we need to figure out the acceleration needed so that at point C, the change in velocity for X = .812 m/s. After we calculate this, we need to find the angle needed for the ramp, and the distance from A-B.
thank you!
I've scanned the lab, and the pictures are below.
Homework Statement
Well, the problem statement is in the picture, I guess...
and our givens are that change in X is .35 meters, change in Y is -.91 meters, acceleration of Y = -9.8m/seconds squared, and initial velocity of Y is 0.
Homework Equations
change in y (or x) = (vi)(t) + (1/2)(a)(time squared)
velocity final = velocity inital + (a)(t)
velocity final squared= velocity inital squared + (2)(a)(change in x or y)
change in y (or x) = (1/2)(velocity final-velocity initial) (t)
The Attempt at a Solution
As seen above, we have calculated the time needed for the ball to go from point C into the pan. From this, we then figured out the initial velocity needed for the X component of the ramp. The distance from B-C (though, it has to be greater than zero so that the Y velocity starts at 0) is irrelevant because the velocity for X is always constant. We have figured the acceleration (Sorry I don't have the work for that, my lab partners do.) out by using the equation "velocity final squared= velocity inital squared + (2)(a)(change in x or y)." I am not sure about this acceleration, though. So, we need to figure out the acceleration needed so that at point C, the change in velocity for X = .812 m/s. After we calculate this, we need to find the angle needed for the ramp, and the distance from A-B.
thank you!