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karush
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$\displaystyle\pi\int_{0}^{\infty} e^x \ dx = \pi$
Ok I looked at some of the template equations but came up with this.
skeeter said:if the curve is $y=e^{-x}$ ...
$\displaystyle V = \pi \int_0^\infty e^{-2x} \, dx = \dfrac{\pi}{2}$
It's a guess that the problem has a typo. The point is that \(\displaystyle e^{-2x}\) is bounded on \(\displaystyle [ 0, \infty )\) whereas \(\displaystyle e^{2x}\) is not.karush said:why is it negative?
karush said:ok
glad you caught it
APC.5.2.01 AP Volume by Rotation is a measurement used in radiology to assess the amount of air in the lungs. It is calculated by multiplying the cross-sectional area of the lungs by the distance between two slices on a CT scan.
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APC.5.2.01 AP Volume by Rotation is measured using a CT scanner, which takes multiple images of the lungs at different angles. These images are then processed using specialized software to calculate the volume of air in the lungs.
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APC.5.2.01 AP Volume by Rotation is a non-invasive procedure and does not have any known risks or side effects. However, as with any medical imaging test, there is a small amount of radiation exposure. The benefits of the test usually outweigh the potential risks.