Assumptions for string vibrator system

In summary: I note that in some cases there is a real node just to the right, in others a virtual node just to the left. It would be interesting to predict that displacement as a function of the parameters.Thank you @haruspex, @BvU, @nasu, and @berkeman for your replies!Sorry for not posting earlier. Here is the figure requested. In summary, when the frequency is slowly increased, the node is fixed at the vibrator end due to resonance.
  • #1
ChiralSuperfields
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Homework Statement
Please see below
Relevant Equations
Please see below
For this,
1682629997163.png

Is it possible to calculate the time it takes for the initial antinode at the string vibrator to become a node in the transient phase of the system? Also do we assume that once the system has reached steady state, that the mass has such a large inertia that it is stationary so acts as a fixed boundary reflecting the waves at a 180-degree phase shift relative to the incident traveling waves?

Many thanks!
 
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  • #2
ChiralSuperfields said:
Is it possible to calculate the time it takes for the initial antinode at the string vibrator to become a node in the transient phase of the system? Also do we assume that once the system has reached steady state, that the mass has such a large inertia that it is stationary so acts as a fixed boundary reflecting the waves at a 180-degree phase shift relative to the incident traveling waves?

Many thanks!
Not sure I understand your first question. The frequency is increased slowly, meaning that when arriving at any given frequency the transient phase to steady state is negligible.
Yes, the movement of the mass is also considered negligible here.
 
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  • #3
Hi,
ChiralSuperfields said:
Is it possible to calculate the time it takes for the initial antinode at the string vibrator to become a node in the transient phase of the system?
That point is as good as fixed. Check with fig 16.29
ChiralSuperfields said:
Also do we assume that once the system has reached steady state, that the mass has such a large inertia that it is stationary so acts as a fixed boundary reflecting the waves at a 180-degree phase shift relative to the incident traveling waves?
The fixed point is at the pulley.
 
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  • #4
How would you have a node at the vibrator end? And where is figure 29? Does it show a node at the vibrator end?
 
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  • #5
nasu said:
How would you have a node at the vibrator end?
Yeah, I don't get that either. How do you drive vibrations on a string from a node?
 
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  • #6
This is practical physics. The string resonates and the deviations from equilibrium at antinodes are much greater than at the vibrator end, so fapp (for all practical purposes) that end is a node. (Thorough experimentation can reveal how near the virtual node is further to the left).



##\ ##
 
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  • #7
BvU said:
The string resonates and the deviations from equilibrium at antinodes are much greater than at the vibrator end, so fapp (for all practical purposes) that end is a node. (Thorough experimentation can reveal how near the virtual node is further to the left).
Huh, TIL. Thanks @BvU :smile:
 
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  • #8
nasu said:
Does it show a node at the vibrator end?
Calling my bluff eh ? :wink:
My reputation is in the hands of @ChiralSuperfields :nb)

##\ ##
 
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  • #9
I asked this before you posted your video. This is better than figure 29, whatever that is.
 
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  • #10
I have played several times with this PHET simulation but I have not relized (until now) that by using a small amplitude of one end you can produce a much higher amplitude at the node.
So, it works even for a simulation, not just in the real world. :smile:

 
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  • #11
nasu said:
I have played several times with this PHET simulation but I have not relized (until now) that by using a small amplitude of one end you can produce a much higher amplitude at the node.
So, it works even for a simulation, not just in the real world. :smile:


I note that in some cases there is a real node just to the right, in others a virtual node just to the left. It would be interesting to predict that displacement as a function of the parameters.
 
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1. What are the main assumptions for a string vibrator system?

The main assumptions for a string vibrator system are that the string is perfectly flexible, inextensible, and homogeneous in material. Additionally, the system is assumed to be in a vacuum with no air resistance or friction.

2. How does the assumption of a perfectly flexible string affect the system?

The assumption of a perfectly flexible string means that the string can bend and deform without any resistance. This allows for a wider range of motion and more complex vibrations in the system.

3. Why is it assumed that the string is inextensible?

The assumption of inextensibility means that the length of the string remains constant throughout the vibrations. This simplifies the mathematical equations used to describe the system and allows for more accurate predictions.

4. What is the significance of assuming a homogeneous string material?

Assuming a homogeneous string material means that the properties of the string, such as density and stiffness, are consistent throughout its length. This allows for easier analysis and calculation of the system's behavior.

5. Are there any limitations to these assumptions for a string vibrator system?

Yes, these assumptions may not accurately represent real-world conditions. In reality, strings may have some degree of flexibility and inextensibility, and there may be air resistance or friction present. However, these assumptions provide a simplified model for understanding the behavior of string vibrator systems.

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