- #1
Wanting to Learn
Homework Statement
:[/B]A ball player catches a ball 3.33 s after throwing it vertically upward.
With what speed did he throw it?
What height did it reach?
Homework Equations
:[/B]d = v0t + .5at2
I'm not sure whether this is one of the equations which should be used for this problem.
[I also have from class (just started AP Physics 1) a list of 5 other equations which I could try to post if that would be helpful, I'm not sure what most of them mean/how any of them could be applied (aside from d=tv).]
gravity 9.8 m/s2 (pulling the ball downwards, not sure how to use this info in solving)
3.33s/2=1.665s ball spends going in each direction (up and down)
The Attempt at a Solution
:[/B]I'm not really sure how to start/what to do with this problem.
I think there need to be 2 parts, going up and going down.
d = 0 + .5*-9.8*1.665 = -8.1585
m • s = m/s
s2
I'm not sure what this number represents, if it does represent anything. I make acceleration negative because of the gravity pulling down but I'm guessing that is not how it needs to be used. Also I think this ignores the acceleration of the ball being thrown up, which was not given, so I'm very confused about what I should do.
Thank you in advance for any and all help.