The initial velocity of the basketball when it is thrown straight up from the ground is equal to the speed at which the basketball is thrown. This can vary depending on the strength and technique of the person throwing the ball.
The maximum height that the basketball will reach when thrown straight up from the ground is determined by the initial velocity and the acceleration due to gravity. Using the equation h = (v2)/(2g), where h is the maximum height, v is the initial velocity, and g is the acceleration due to gravity (9.8 m/s2), we can calculate the height.
At the maximum height, the basketball's velocity will be zero. This means that the ball will momentarily stop moving before falling back to the ground due to the force of gravity. The ball will follow the same path back to the ground as it did when it was thrown up.
The time it takes for the basketball to reach its maximum height can be calculated using the equation t = v/g, where t is the time, v is the initial velocity, and g is the acceleration due to gravity. However, this only gives the time for the ball to reach its maximum height, not the total time it takes for the ball to return to the ground.
Yes, the basketball's trajectory can be affected by external factors such as air resistance, wind, and spin. These factors can alter the ball's speed and direction, causing it to deviate from its expected path. The ball's trajectory can also be affected by the surface it bounces off of when it falls back to the ground.