Calculate mEq/L of Ba from BaBr2

  • Thread starter cmgbruschi
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In summary, the question asks for the concentration of Ba in mEq/L in a solution of BaBr2. To solve this, the amount of Ba in grams needs to be determined first. Since 1 mole of BaBr2 contains 2 moles of Ba, the .8753 g of BaBr2 would contain .617 g of Ba. This can then be converted to moles and the concentration in mEq/L can be calculated. The number of equivalents does not necessarily correspond to the charge on ions generated, as seen in the example of H3PO4.
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cmgbruschi
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Homework Statement

Barium bromide BaBr2 (875.3 mg) was dissolved in water to make one liter of solution. Express the concentration in the following units: mEq/L of Ba.



Homework Equations

Ba has a charge of 2+ which means it has 2 Eq in 1 mole.



The Attempt at a Solution

First I changed the 875.3 mg into .8753 g of BaBr2. The thing that really confuses me is how do I know how many grams of Ba is in .8753 g of BaBr2? I understand how to do this problem if it asked for the mEq/L of BaBr2, but I'm stuck because I can't figure out how many grams of just Ba is in .8753g of BaBr2. Once I figure out the g of Ba I can convert it into moles since there are 137.3 g per mole of Ba.
 
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  • #2
Why couldn't you do the same thing for BaBr2? Equivalents don't 'equate' to charge either.

example

H3PO4 <-------> 3H+ + PO4-3

In this example, there are three equivalents of H+ per mole of H3PO4 and only one equivalent of PO4-3. Notice how the number of equivalents are unrelated to the charge on the ions generated?
 

Related to Calculate mEq/L of Ba from BaBr2

1. How do you calculate mEq/L of Ba from BaBr2?

To calculate the mEq/L of Ba from BaBr2, you need to first determine the molecular weight of BaBr2. This can be done by adding the atomic weights of each element (Ba = 137.33 g/mol, Br = 79.90 g/mol) to get a total of 217.23 g/mol. Then, divide the given concentration of BaBr2 (in g/L) by the molecular weight to get the mEq/L of Ba.

2. What is the purpose of calculating mEq/L of Ba from BaBr2?

The purpose of calculating mEq/L of Ba from BaBr2 is to determine the concentration of barium ions (Ba2+) in a solution. This is important in various scientific and medical applications, such as in determining the effectiveness of barium-based medications or in analyzing the water quality in a lab.

3. Can mEq/L of Ba be converted to other units of concentration?

Yes, mEq/L of Ba can be converted to other units of concentration, such as millimoles per liter (mmol/L) or parts per million (ppm). This conversion can be done by using the molar mass of Ba (137.33 g/mol) and the desired unit of measurement in the conversion factor.

4. What is the difference between mEq/L and mg/L?

mEq/L and mg/L are both units of concentration, but they measure different quantities. mEq/L (milliequivalents per liter) measures the number of charged particles (ions) in a solution, while mg/L (milligrams per liter) measures the mass of a substance in a solution. To convert between the two, you need to know the molecular weight of the substance.

5. How does the concentration of BaBr2 affect the mEq/L of Ba?

The concentration of BaBr2 directly affects the mEq/L of Ba. The higher the concentration of BaBr2, the higher the mEq/L of Ba will be. This is because a higher concentration of BaBr2 means there are more barium ions present in the solution, resulting in a higher mEq/L of Ba.

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