Calculating Entropy of a System: What to Do?

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Calculating the entropy of an object like an apple involves determining the number of microscopic arrangements of its particles, represented by Boltzmann's formula S = k ln N, where k is Boltzmann's constant. The second law of thermodynamics indicates that entropy tends to increase, meaning the apple will eventually rot, reflecting a transition from order to disorder. The precision of the description of the apple affects the number of compatible states, but changes in entropy are minimal, often insignificant in practical terms. Alternative methods include using classical thermodynamics to integrate heat capacity over temperature or considering the entropy of its components. The discussion also raises the question of whether measuring combustion products could help infer the apple's original entropy.
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What would you do if you were asked to calculate the entropy of an object such as an apple? Does the question even make sense?
 
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If it makes sense. What does it mean?
 
In accordance with the second law of entropy the apple would move from order to disorder, which simply means that eventually it will go rotten.
 
It makes sense. What it means is taking the natural log of the multiplicity(the number of way of arranging things in the system) multiplied by Boltzmann's constant. S = k*ln(omega)

The second law of thermodynamics says that this number tends to increase. So like Tzemach said, the apple will rot.
 
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pivoxa15 said:
What would you do if you were asked to calculate the entropy of an object such as an apple? Does the question even make sense?

Well, you'd have to count all the different microscopic arrangements of the particles in the apple which would still be compatible with your description of "apple". This number, N, is then entered in Boltzman's formula:

S = k ln N

with k = Boltzmann's constant, and it will give you the entropy.
k = 1.38 10^(-23) Joule/Kelvin

As you see, the concept of entropy is in principle dependent of the precision by which you describe your apple, but this is usually taken as "macroscopically distinct" descriptions. And, when you look at it numerically, it really doesn't change much the value of S when you add, or leave out, an extra macroscopic specification.
This is because even if your macroscopic description changes the number N of compatible states, by, say, a factor 10^50, this would only change your entropy by k x ln 10^50 ~ k x 150 ~ 10^(-20) Joule/Kelvin, an utterly small amount of entropy.
 
Or, you skip the stat mech, stick to old-fashioned, "smash-mouth" thermo, and integrate C/T from absolute zero to room T; or, add the third law entropies for 130-140 grams of water, 50-60 grams of sugars, and other organic compounds, plus an entropy of mixing term (sum of R(xlnx)), where x = mole fraction), and go on your merry way.
 
And what about burning it in a lab?
Could the measurement of the combustion product allow backflushing to the entropy of the apple?
Any idea about it?
 
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