Calculating Linear Charge Density of a Cylinder

AI Thread Summary
The discussion focuses on calculating the linear charge density of an infinitely long cylinder with a given volume charge density. The linear charge density is derived from the volume charge density by multiplying it with the cylinder's cross-sectional area, leading to the expression λ = πR²ρ₀(α - r/β). There is a concern that this method only applies if the charge density is uniform across the cylinder's cross-section. The conversation also highlights the need to use Gauss's Law for determining the electric field in parts b and c, emphasizing the importance of understanding the charge distribution. The participant expresses uncertainty about proceeding with parts b and c without confidence in part a.
chichiba
Messages
1
Reaction score
0
Homework Statement
An infinitely long cylinder carries a charge density throughout its volume given by:
𝜌(𝑟) = 𝜌0 (𝛼 − 𝑟 /𝛽)
where 𝑟 is the radial distance from its central axis and 𝜌0, 𝛼, and 𝛽 are positive constants. The radius of the cylinder is 𝑅 beyond which the charge density is zero.
(a) Obtain an expression for the linear charge density of the cylinder.
(b) Obtain expressions for the electric field inside (𝑟 < 𝑅) and outside (𝑟 > 𝑅) the cylinder.
(c) Taking 𝑉(𝑅) = 0 as the reference, get the potential of the cylinder for points inside and outside the cylinder.
Relevant Equations
Linear charge density, Gauss's Law
For part a:

I know that linear charge density is the amount of charge per unit length, and we are given the volume charge density. Since we are given the volume, we can obtain the length by multiplying the volume by the cross sectional area, so C/m^3 * m^2 = C/m. The cross sectional area of a cylinder is A= πR^2, so we can get the linear charge density by solving for λ=𝜌A, and multiply our area by our initial equation to get:

λ = πR^2 𝜌0 (𝛼 − 𝑟/𝛽)

I haven't began part b or c yet, because I am not confident in part a. I do think that in both cases, for r>R (outside of the cylinder), that the electric field and potential would be zero, because R is beyond where the charge density is zero.

I also know to use Gauss's Law for part b, and integration for part c, but am not entirely sure where to begin.

Thank you!
 
Physics news on Phys.org
chichiba said:
Homework Statement:: An infinitely long cylinder carries a charge density throughout its volume given by:
𝜌(𝑟) = 𝜌0 (𝛼 − 𝑟 /𝛽)
where 𝑟 is the radial distance from its central axis and 𝜌0, 𝛼, and 𝛽 are positive constants. The radius of the cylinder is 𝑅 beyond which the charge density is zero.
(a) Obtain an expression for the linear charge density of the cylinder.
(b) Obtain expressions for the electric field inside (𝑟 < 𝑅) and outside (𝑟 > 𝑅) the cylinder.
(c) Taking 𝑉(𝑅) = 0 as the reference, get the potential of the cylinder for points inside and outside the cylinder.
Relevant Equations:: Linear charge density, Gauss's Law

For part a:

I know that linear charge density is the amount of charge per unit length, and we are given the volume charge density. Since we are given the volume, we can obtain the length by multiplying the volume by the cross sectional area, so C/m^3 * m^2 = C/m. The cross sectional area of a cylinder is A= πR^2, so we can get the linear charge density by solving for λ=𝜌A, and multiply our area by our initial equation to get:

λ = πR^2 𝜌0 (𝛼 − 𝑟/𝛽)
Your method for finding ##\lambda## will only work if ##\rho## is uniform across a cross section of the cylinder.

Consider a section of the cylinder of infinitesimal length ##dx## and let ##dQ## be the total charge contained within this section. ##\lambda = dQ/dx##.

1674847382907.png


Can you use ##\rho(r)## to find an expression for ##dQ##?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top