- #1
Diamond101
- 25
- 0
Homework Statement
1. (a) From the following data, 2 Cu (s) + S (s) Cu2S (g) ∆rH° = - 79.5 kJ mol-1 S (s) + O2(g) SO2 (g) ∆rH° = - 296.8 kJ mol-1 Cu2S (s) + 2 O2(g) 2CuO (s) + SO2(g) ∆rH° = - 527.5 kJ mol-1 Determine ∆rH° for Cu(s) + ½ O2 (g) CuO (s) at 298 K
(b) Given the following Cp / (J K-1 mol-1) Cu(s) = 24.44 O2(g) = 29.36 CuO (s) = 42.30 Calculate the ∆rH° for the reaction at 1000K.
Homework Equations
More so part b is it correct
The Attempt at a Solution
2 Cu (s) + S (s) ---> Cu2S (g) ∆rH° = - 79.5 kJ mol-1
SO2 (g) ---> S (s) + O2(g) ∆rH° = +296.8 kJ mol-1
Cu2S (s) + 2 O2(g) ---> 2CuO (s) + SO2(g) ∆rH° = - 527.5 kJ mol-1
Adding the above three equations results in this:
2 Cu (s) + O2(g) ---> 2CuO (s) ∆rH° = -310.2 kJ
Dividing through by 2 = -155.1 kJ.
part b cu(s) =+79.5 =24.4 (1000-298 k) using the equation ∆rHT2=∆rHT1+∆CP(T2-T1)
SAME GOES FOR O2 and CUO ?