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mach6
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What would be the approximate force required on the perimeter of a 30 ft diameter table that weighs 200,000 lbs to move it? The table is sitting on twelve wheels (10" diameter each) that are mounted to ball bearings.
The force required to move a 200,000 lb table on 12 wheels can be calculated using the formula F = μ * N, where F is the force, μ is the coefficient of friction, and N is the normal force. The coefficient of friction is a constant value that depends on the type of surface the table is being moved on, while the normal force is the weight of the table divided by the number of wheels it is resting on.
The coefficient of friction for moving a 200,000 lb table on 12 wheels can vary depending on the surface the table is being moved on. Generally, for a smooth, flat surface, the coefficient of friction can range from 0.01 to 0.05. However, for surfaces with more friction, such as carpet or grass, the coefficient of friction can be higher.
The normal force for a 200,000 lb table on 12 wheels can be determined by dividing the weight of the table (200,000 lbs) by the number of wheels it is resting on (12). This will give you the amount of force pushing down on each wheel, which is important in calculating the overall force required to move the table.
No, the force required to move a 200,000 lb table on 12 wheels can vary depending on the surface it is being moved on. This is because the coefficient of friction changes based on the type of surface, as well as other factors such as the weight distribution of the table and the condition of the wheels.
Yes, there are several other factors that can affect the force required to move a 200,000 lb table on 12 wheels. These include the condition of the wheels (e.g. worn out or properly lubricated), the angle of the surface (e.g. if the table is being moved on an incline), and any additional forces acting on the table (e.g. wind or other external forces).