Calculating the Spring Constant from Force-Extension Graph

AI Thread Summary
The discussion revolves around calculating the spring constant (k) from a force-extension graph using the formula k = F/x. A user plotted the data and calculated a gradient of 26.3 N/m but found discrepancies when comparing this to their calculated values for k. They noted that the graph does not intersect at the origin (0,0), which may contribute to the differences. The teacher suggested starting calculations from a force of 0.5 N to reduce errors, indicating that this approach could lead to more accurate results. The user plans to adjust their data accordingly to improve their calculations.
Jadaa
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Homework Statement


Force Extension in (m)
1.0 0.014.
1.5 0.032.
2.0 0.053.
2.5 0.071.
3.0 0.090.
3.5 0.110.
4.0 0.130.
4.5 0.148.
5.0 0.166.

Homework Equations


RESULTS FROM GRAPH.
F= kx.
k=F/x,m= vertical side/ horizontal rise.

The Attempt at a Solution


I plotted a graph of force against extension and found the gradient to be 26.3N/m using the points (0.014,0.1) and (0.166,0.5).
It's my understanding that the gradient should be equal to the answer obtained from k= F/x but when I work it out the answers are not similar and I'm not sure where I went wrong.
 
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Jadaa said:
but when I work it out the answers are not similar
Can you explain what that means. Does that mean that your answer is significantly different than the book?
 
TomHart said:
Can you explain what that means. Does that mean that your answer is significantly different than the book?

When I work it out it's not equal to the gradient which my teacher says it should be. I think it's because I'm not sure how to probably use the formula when there are so many quantities.
 
I plotted the data. It appears that it doesn't intersect at x=0, F=0 very well. That has to be what is causing the discrepancy.
 
TomHart said:
I plotted the data. It appears that it doesn't intersect at x=0, F=0 very well. That has to be what is causing the discrepancy.

Ooo I see my teacher has advised us that we could have started from 0.5 F instead of 0 instead as we were getting errors. Thank you I'll try to recover my previous set of data.
 
That should help because if I find an equation for the line based on the 26.3 slope, it shows an offset of 0.63 N.
 
Thanks again
 
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