Calculating Uncertainty of Mean for 0.5 mm Ruler Measurements

In summary, the conversation discusses the uncertainty of a ruler with a precision of ± 0.5mm and how it affects calculations and reporting of data. It also brings up the distinction between systematic and random errors and how to account for them in calculations. The document provides a formula for calculating the uncertainty of the mean for multiple data sets. However, it is noted that the example of measuring the perimeter of a fence may not directly apply to this situation and further clarification or additional information may be needed.
  • #1
utp9
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I am following this: avntraining.hartrao.ac.za/images/Error_Analysis.pdf

I have a ruler with an uncertainty of ± 0.5mm. I made a calculation subtracting one measurement of the ruler, from another measurement, making the uncertainty for the data ± 1.0mm.

As I have four trials, I calculated the mean. Hence, I must calculate the uncertainty of the mean. Using the formula given in the document would the uncertainty be just that, or do I add the rulers uncertainty as well?

Example:
Using the Δxavg formula I get a uncertainty of 0.2 mm (rounded). So would that be my uncertainty? Or, do I add the rulers uncertainty after the first equation, so 1.0 mm to it, to get ± 1.2 mm?
 
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  • #2
utp9 said:
I have a ruler with an uncertainty of ± 0.5mm
Do you know about the distinction between systematic errors and random errors ?

[edit]well, you must, because the word document you refer to is treating it. In your example you achieve a precision of 0.2 mm, but if the ruler is 0.5 mm off, that last error is common to all observations. So you can report ##x\pm 0.2 _{( {\sf stat})} \pm 0.5 _{( {\sf syst})} ##.
In case you want to report a single error, add in quadrature (resulting in ##\pm 0.5## too because of rounding).
 
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  • #3
This is a situation where we must choose between giving advice about how to follow a set of directions (http://avntraining.hartrao.ac.za/images/Error_Analysis.pdf) vs discussing the complicated mathematics that lies behind that set of directions and perhaps advising that they be disobeyed or improved.

Taking the former course:

utp9 said:
I have a ruler with an uncertainty of ± 0.5mm. I made a calculation subtracting one measurement of the ruler, from another measurement, making the uncertainty for the data ± 1.0mm.

If you judge the "uncertainty" of the ruler by half the distance between its finest graduations, the example of measuring the distance between the legs of the grasshopper makes it clear that the "uncertainty" in the distance measurement is not to be calculated as ##\pm (0.5 + 0.5)##, but rather as ##\pm \sqrt{ 0.5^2 + 0.5^2}##.

As I have four trials, I calculated the mean. Hence, I must calculate the uncertainty of the mean. Using the formula given in the document would the uncertainty be just that
Just what? What formula?
Are you referring to the example where the uncertainty of the mean is calculated for two data sets? In that example, the uncertainty of the mean for each data set is calculated by ##\frac{R}{2 \sqrt{N}}##, where ##R## is the maximum measurement minus the minimum measurement and ##N## is the number of measurments.

or do I add the rulers uncertainty as well?

That's a good question! The example of measuring perimeter of a fence shows how to account for (not literally "add") the uncertainties in individual measurements. However the measurements of the different sides are not each measurements of the same thing. Is there more material in the text? We need an example where several measurements of the same thing are taken, each with given uncertainty.
 
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  • #4
BvU said:
Do you know about the distinction between systematic errors and random errors ?

[edit]well, you must, because the word document you refer to is treating it. In your example you achieve a precision of 0.2 mm, but if the ruler is 0.5 mm off, that last error is common to all observations. So you can report ##x\pm 0.2 _{( {\sf stat})} \pm 0.5 _{( {\sf syst})} ##.
In case you want to report a single error, add in quadrature (resulting in ##\pm 0.5## too because of rounding).
Stephen Tashi said:
This is a situation where we must choose between giving advice about how to follow a set of directions (http://avntraining.hartrao.ac.za/images/Error_Analysis.pdf) vs discussing the complicated mathematics that lies behind that set of directions and perhaps advising that they be disobeyed or improved.

Taking the former course:
If you judge the "uncertainty" of the ruler by half the distance between its finest graduations, the example of measuring the distance between the legs of the grasshopper makes it clear that the "uncertainty" in the distance measurement is not to be calculated as ##\pm (0.5 + 0.5)##, but rather as ##\pm \sqrt{ 0.5^2 + 0.5^2}##.Just what? What formula?
Are you referring to the example where the uncertainty of the mean is calculated for two data sets? In that example, the uncertainty of the mean for each data set is calculated by ##\frac{R}{2 \sqrt{N}}##, where ##R## is the maximum measurement minus the minimum measurement and ##N## is the number of measurments.
That's a good question! The example of measuring perimeter of a fence shows how to account for (not literally "add") the uncertainties in individual measurements. However the measurements of the different sides are not each measurements of the same thing. Is there more material in the text? We need an example where several measurements of the same thing are taken, each with given uncertainty.

Would something like this work?
Annotation 2020-04-13 160408.png

Or would that contradict this?
Annotation 2020-04-13 160532.png

I have equations for the rest of the quantities before Table 5 employed in previous tables. Hence, whey there is only one equation and calculation.

Thanks for the replies :)
 
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  • #5
utp9 said:
Would something like this work?
Hard to say without explanation what all this is and how it came about.
 
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  • #6
utp9 said:
As I have four trials,
I don't understand how "four trials" relates to the chart for your data. What is the definition of a "trial"? Was each trial a measurement performed on the same object?
 
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  • #7
BvU said:
Hard to say without explanation what all this is and how it came about.
Stephen Tashi said:
I don't understand how "four trials" relates to the chart for your data. What is the definition of a "trial"? Was each trial a measurement performed on the same object?

I apologize, obviously you can't see what I have written down.
I actually read the whole PDF document, instead of just browsing over it and now I understand what I'm supposed to do.

Here's the data I was referring to:
Annotation 2020-04-13 191843.png
Annotation 2020-04-13 192057.png

What I've done here is logical, right?
I can now use Δxavg in my graphs for error bars?
 
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  • #8
utp9 said:
and now I understand what I'm supposed to do.

If what your are supposed to do is to follow the rules set out in the document, I think you have followed them correctly as far as computing individual "uncertainties". The author of document doesn't say how to compute the length of error bars.

Using your notation, my guess is that the author would compute the "uncertainty" of the average of N measurements, each of which has an uncertainty of ##\triangle z_{sys}## associated with it as: ##\sqrt{ (\triangle x_{avg})^2 + \frac{ (\triangle z_{sys})^2} {N} }##. We should ask for other opinions!

What I've done here is logical, right?

The document you have (like many others) does not give reasons that justify rules for computing uncertainties. To justify the rules in a logical manner requires a sophisticated knowledge of mathematical statistics. Before we can prove that a rule provides a "good" or "correct" estimate, we must define what "correctness" or "goodness" mean in a statistical context. That alone is not a simple task. My guess is that your studies don't ask you to do this yet.
 
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1. How do I calculate the uncertainty of mean for 0.5 mm ruler measurements?

The uncertainty of mean for 0.5 mm ruler measurements can be calculated by taking the standard deviation of the measurements and dividing it by the square root of the number of measurements. This will give you the uncertainty of each measurement.

2. Why is it important to calculate the uncertainty of mean for 0.5 mm ruler measurements?

Calculating the uncertainty of mean for 0.5 mm ruler measurements is important because it gives us an idea of how accurate our measurements are. It helps us understand the potential errors in our measurements and allows us to make more informed conclusions based on our data.

3. What factors can affect the uncertainty of mean for 0.5 mm ruler measurements?

There are several factors that can affect the uncertainty of mean for 0.5 mm ruler measurements, including the precision of the ruler, the skill of the person taking the measurements, and any external factors that may impact the measurements (e.g. temperature, humidity, etc.). It is important to control for these factors as much as possible to minimize uncertainty.

4. Can the uncertainty of mean for 0.5 mm ruler measurements be reduced?

Yes, the uncertainty of mean for 0.5 mm ruler measurements can be reduced by taking more measurements and increasing the sample size. This will help to decrease the impact of any outliers or errors in individual measurements. Additionally, using more precise instruments and ensuring proper measurement techniques can also help to reduce uncertainty.

5. How can I use the uncertainty of mean for 0.5 mm ruler measurements in my data analysis?

The uncertainty of mean for 0.5 mm ruler measurements can be used in data analysis by calculating the confidence interval, which gives a range of values within which the true mean is likely to fall. This can help to determine the significance of any differences between groups or to compare results to a known value. It can also be used to determine the precision of the measurements and the overall reliability of the data.

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