Can I apply Bernoulli's equation to rigid body rotation?

In summary, the problem statement is trying to find a mathematical relationship between the pressure gradient and the speed of the water, but Bernoulli's equation doesn't work because the lowest pressure and lowest speed occurs near the center of the bucket. A force balance in the radial direction would do the trick.
  • #1
RAP1234
9
0
1. The problem statement, all variables and given/know

Say I have a can of water, and I am rotating it about its central axis at a constant angular rate. The water in the tank should make a 3D almost parabolic curve as it touches the the walls of the tank. Can I use Bernoulli's equation along y=0, r =0 ( starting from the minima of my parabola) to the radius (r=R) to solve a problem involving this system? Is P = (1/2) + rho*v^2 = const valid?


Homework Equations



P = (1/2) + rho*v^2 = const

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rig_roth.gif


The Attempt at a Solution



I would think P = (1/2) + rho*v^2 = const may be valid because

if the fluid is rotating with the tank as a rigid body, assuming we are looking at it after it has been spun up and is rotating with constant angular rate, then it is at steady state?

The density of the fluid I am assuming is constant.

I am assuming viscosity is negligible

Are the streamlines just circles and I'm going normal to them?

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  • #2
Yes, the streamlines are circles, and you're going normal to them.

Chet
 
  • #3
I had the impression that the inner fluid has a faster rate of rotation than the outer fluid. Also streamlines aren't really streamlines if they are curved. Curvature requires a pressure gradient perpendicular to the direction of flow, and Bernoulli doesn't deal with that. Viscosity is going to have an effect, since different parts of the fluid are moving at different speeds.
 
  • #4
rcgldr said:
I had the impression that the inner fluid has a faster rate of rotation than the outer fluid.
Once the system reaches steady state, the fluid will be rotating like a rigid body, and the angular velocity will be constant throughout the fluid. Of course the circumferential velocity will be equal to the angular velocity times the radial location.
Also streamlines aren't really streamlines if they are curved.
What could possibly have made you think this? It simply is not correct.
Viscosity is going to have an effect, since different parts of the fluid are moving at different speeds.
Viscosity won't be a factor once the system reaches steady state and the fluid is rotating like a rigid body.

Chet
 
  • #5
rcgldr said:
I had the impression that the inner fluid has a faster rate of rotation than the outer fluid.
Chestermiller said:
Once the system reaches steady state, the fluid will be rotating like a rigid body
OK, don't recall where I read about this before that gave me the false impression.

rcgldr said:
Also streamlines aren't really streamlines if they are curved. Curvature requires a pressure gradient perpendicular to the direction of flow, and Bernoulli doesn't deal with that.

Chestermiller said:
What could possibly have made you think this? It simply is not correct.
I thought this was mentioned in one or more prior threads about wings and lift. Maybe it was in reference to how lift calculations are based on streamline velocities just outside the boundary layer of a wing and the fact that the streamlines had to be broken up into small componennts along the wing chord to deal with the effects of curvature. I think the issue was that the flow past a cross section of a streamline was supposed to be constant, but if the streamline is curved, the pressure is lower and the flow rate faster on the inner part of the streamline.

Back to the spinning bucket with water. Assuming the angular velocity is constant, then the lowest pressure and lowest speed occurs near the center of the bucket, which would violate Bernoulli, so some other method would need to be used to find a mathematical relationship between the pressure gradient and the speed of the water.
 
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  • #6
rcgldr said:
OK, don't recall where I read about this before that gave me the false impression.
You were probably reading about flow between concentric rotating cylinders.
Back to the spinning bucket with water. Assuming the angular velocity is constant, then the lowest pressure and lowest speed occurs near the center of the bucket, which would violate Bernoulli, so some other method would need to be used to find a mathematical relationship between the pressure gradient and the speed of the water.
A force balance in the radial direction would do the trick.

Rap1234: Have you learned about the Equations of Motion in cylindrical coordinates yet? If not, this can still be analyzed by doing a force balance on an element between r and r + dr, and θ and θ+dθ.

Chet
 

1. Can I apply Bernoulli's equation to rigid body rotation?

Yes, Bernoulli's equation can be applied to rigid body rotation as long as the flow is steady and inviscid.

2. What is Bernoulli's equation?

Bernoulli's equation is a fundamental equation in fluid mechanics that relates the pressure, velocity, and elevation of a fluid in a steady flow.

3. How is Bernoulli's equation derived?

Bernoulli's equation is derived from the conservation of energy principle, which states that the total energy of a system remains constant.

4. What is the significance of applying Bernoulli's equation to rigid body rotation?

Applying Bernoulli's equation to rigid body rotation allows for the analysis and prediction of the behavior of fluids in rotational motion, such as airfoils and turbines.

5. Are there any limitations to using Bernoulli's equation for rigid body rotation?

Yes, Bernoulli's equation assumes that the flow is steady, inviscid, and incompressible, which may not always be the case for real-world fluid systems.

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