- #1
Micmic85
Hi everybody,
Consider the situation illustrated in the attached figure . A large water tank at elevation z1 is connected to a penstock with diameter D and outlet at elevation z2. The flow in the penstock is Q. The outlet of the pipe is connected to a valve and nozzle that direct a jet of water to an impulse turbine. Yes, the most basic stuff...
Let's assume that we remove the nozzle and valve at the outlet of the pipe. Q is in that case the natural flow in the pipe, i.e. the maximum flow that a pipe of a given diameter can carry under the sole action of gravity. From the book of Jones, Gravity Driven Water Flows in Networks, the power generated by the turbine in that case would be 0...I cannot understand this as the water coming out of the pipe has some velocity and carries then kinetic energy that could be used to rotate the turbine. Can someone clarify?
Thanks
Consider the situation illustrated in the attached figure . A large water tank at elevation z1 is connected to a penstock with diameter D and outlet at elevation z2. The flow in the penstock is Q. The outlet of the pipe is connected to a valve and nozzle that direct a jet of water to an impulse turbine. Yes, the most basic stuff...
Let's assume that we remove the nozzle and valve at the outlet of the pipe. Q is in that case the natural flow in the pipe, i.e. the maximum flow that a pipe of a given diameter can carry under the sole action of gravity. From the book of Jones, Gravity Driven Water Flows in Networks, the power generated by the turbine in that case would be 0...I cannot understand this as the water coming out of the pipe has some velocity and carries then kinetic energy that could be used to rotate the turbine. Can someone clarify?
Thanks