Convert linear density to area and volumetric density?

AI Thread Summary
To convert area density to linear and volumetric density, the shape of the object is crucial; in this case, it is a flat square surface. The total mass can be calculated using the formula M = σA, where σ is the area density and A is the area. The volumetric density is derived as ρ = σ/T, with T representing the thickness of the plate. Linear density is only constant along the direction parallel to one side of the plate. Understanding these relationships allows for accurate conversions between different density types.
silverdiesel
Messages
64
Reaction score
0
if I am given a area density of 10^-4, I can get linear and volumetric density from that right? I just can't seem to figure it out.
 
Physics news on Phys.org
silverdiesel said:
if I am given a area density of 10^-4, I can get linear and volumetric density from that right? I just can't seem to figure it out.
Only if you know the shape of an object you are working on.
 
It is a square (not a cube, a flat square surface)
 
silverdiesel said:
It is a square (not a cube, a flat square surface)
Then the total mass of the object is

M = σA

The volume density is

ρ = M/V = σA/V = σA/(AT) = σ/T

where T is the thickness of the plate.

If you want the linear density, it is only constant in a direction parallel to one side of the plate. See if you can do that one.
 

Thread 'Rolling without slipping on a curved surface'

Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Calculating Linear Charge Density of a Cylinder
Replies
1
Views
3K
Coulomb's law to find electric field for charge density function
Replies
11
Views
1K
Volumetric flow of a overflowing cone
Replies
6
Views
2K
Induction heat flux density induced by wire in a slab
Replies
0
Views
825
Surface density of stars in a Galaxy
Replies
1
Views
2K
Density function, calculating the mass
Replies
9
Views
2K
Solving the Mystery of a Floating Bottle: Density & Volume
Replies
15
Views
2K
Ice Core Density Problem (Inspired by NEEM)
Replies
6
Views
536
The density of a proton (hydrogen nucleus)
Replies
9
Views
2K
Expanding explosion from an Asteroid
Replies
13
Views
2K

Hot Threads

Recent Insights

Back
Top