- #1
pyroknife
- 613
- 3
I am interested in polyhedrons (mostly hexahedrons and pentahedrons). The shapes I am interested in are irregular, where none of the opposing faces are parallel to each other. However, the shapes I am dealing with all CONVEX.
I have the vertices of my polyhedrons and was wondering if I sum up all the vertices and divide by the number of vertices (averaging), would the resulting averaged (x,y,z) coordinate always be inside the convex polyhedron formed by the vertices that were averaged?
I have the vertices of my polyhedrons and was wondering if I sum up all the vertices and divide by the number of vertices (averaging), would the resulting averaged (x,y,z) coordinate always be inside the convex polyhedron formed by the vertices that were averaged?