Cooling a gas by releasing it into vacuum: Entropy?

In summary: ERICAN ENERGY COSTSIn summary, the American energy costs are high because of the high cost of energy.
  • #1
greypilgrim
516
36
Hi.

I just read an article where following cooling method is described. Apparently it's very common, but I don't know what it's called:

A gas under pressure is released into a vacuum through a small hole. The average particle speed in this beam of gas is the same as before, but the distribution is much narrower, and also all particles move in about the same direction. Although the energy didn't change, the temperature of the gas is much lower than before, because an observer flying next to the beam with the average particle speed would only see slowly moving particles.
In short, thermal energy has been converted into kinetic energy.

Now this seems a lot like the entropy of the gas decreased. The process looks irreversible though, so there surely must be a bigger entropy increase somewhere, but where? I suspect it's probably the increase in volume, but in the illustrations in the article the particle beam looks very narrow and the particles pretty localized.
 
Science news on Phys.org
  • #2
I'm not sure about how you would calculate it, but do you think you could heat up the stream of particles, and they would shoot back into the tiny hole in the container? The answer to this should give you some insight to what is happening with the entropy.
The following video has a pretty interesting explanation of how entropy works.
 
  • #3
greypilgrim said:
Hi.
I suspect it's probably the increase in volume, but in the illustrations in the article the particle beam looks very narrow and the particles pretty localized.

Then there is an error.

Small hole: Particles fly in all directions.

A nozzle: Particle beam expands more slowly than in the previous case.

A very large nozzle: Particle beam expand very slowly after leaving the nozzle. Particle beam's thickness near the nozzle is about the same as nozzle's diameter.
 
  • #4
A beam of particles is not going to stay in a narrow beam unless something is forcing to stay in that beam - a pipe for example. Otherwise, when particles bang into each other, some will bounce in a different direction than the main beam, causing the group of particles to spread.
 
  • #5
scottdave said:
A beam of particles is not going to stay in a narrow beam unless something is forcing to stay in that beam - a pipe for example. Otherwise, when particles bang into each other, some will bounce in a different direction than the main beam, causing the group of particles to spread.

Beams where particles collide behave the same way as beams where particles do not collide, because ... both beams are made of gas. Pressure of beam does not matter. Temperature matters.
 
  • #6
greypilgrim said:
A gas under pressure is released into a vacuum through a small hole. The average particle speed in this beam of gas is the same as before, but the distribution is much narrower, and also all particles move in about the same direction. Although the energy didn't change, the temperature of the gas is much lower than before, because an observer flying next to the beam with the average particle speed would only see slowly moving particles.
In short, thermal energy has been converted into kinetic energy.
Your example illustrates the principle behind the Bernoulli equation which is about conservation of energy. The pressure in the gas that passes into the vacuum drops to 0 and freely expands into the vacuum. After leaving the hole the gas molecules travel in all directions except backward (i.e over a 180 degree range) so the centre of mass of the expelled gas moves away from the hole at an average speed given by Bernoulli's equation. It is not in an equilibrium state so its temperature is undefined. If and when it settles down into its new larger volume, however, it is ends up in an equilibrium state. And if it is an ideal gas it will end up at its original temperature.
Now this seems a lot like the entropy of the gas decreased. The process looks irreversible though, so there surely must be a bigger entropy increase somewhere, but where? I suspect it's probably the increase in volume, but in the illustrations in the article the particle beam looks very narrow and the particles pretty localized.
The change in entropy is defined only between equilibrium states. You have not defined your final equilibrium state. The entropy of the gas expanding indefinitely into a vacuum is undefined. If and when it settles down into an equilibrium state with a larger volume, it will have increased entropy.

AM
 
  • Like
Likes GAURAV DADWAL

1. How does releasing a gas into a vacuum cause it to cool down?

When a gas is released into a vacuum, it expands and its particles spread out, decreasing the density of the gas. This causes a decrease in temperature, as the particles have more space to move around and collide with each other less frequently. This decrease in temperature is known as adiabatic cooling.

2. What is the role of entropy in cooling a gas by releasing it into vacuum?

Entropy is a measure of the disorder or randomness of a system. When a gas is released into a vacuum, its entropy increases as the particles spread out and become more disordered. This increase in entropy is directly related to the decrease in temperature, as the gas becomes less organized and cooler.

3. How does the temperature of the gas affect the rate of cooling when released into a vacuum?

The temperature of the gas plays a crucial role in the rate of cooling when released into a vacuum. A gas at a higher temperature will have more thermal energy, and therefore more kinetic energy, causing it to expand and cool down more rapidly compared to a gas at a lower temperature.

4. Does the type of gas being released into a vacuum affect the cooling process?

Yes, the type of gas does have an impact on the cooling process when released into a vacuum. Different gases have different molecular weights and properties, which can affect their expansion rate and therefore their cooling rate. For example, lighter gases such as helium will cool down faster than heavier gases like carbon dioxide.

5. Is it possible to completely cool a gas by releasing it into a vacuum?

No, it is not possible to completely cool a gas by releasing it into a vacuum. While the gas will experience adiabatic cooling, it will eventually reach a temperature known as the "background temperature" of the vacuum, which is typically around 3 Kelvin. This is the lowest temperature that can be achieved by any cooling method.

Similar threads

Replies
56
Views
3K
Replies
22
Views
2K
Replies
1
Views
769
Replies
4
Views
957
Replies
3
Views
1K
  • Thermodynamics
Replies
5
Views
962
Replies
5
Views
2K
Replies
12
Views
2K
Replies
2
Views
847
  • Thermodynamics
Replies
26
Views
1K
Back
Top