Why is entropy of an object inversely related to its temperature?

In summary, the conversation discusses the relationship between entropy, temperature, and heat capacity in various systems. It is noted that the entropy of an object is inversely proportional to its temperature, and that this statement may not apply to all systems. Negative heat capacity is also discussed, with the understanding that it would require a specific function to produce a reciprocal relationship between entropy and temperature. Ultimately, it is concluded that there is no known material with this property, but that it may apply to gravitationally bound systems. The conversation ends with a note on the interesting nature of physics and the analysis of these concepts.
  • #1
KurtLudwig
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I read in a book "Quantum Space" by Jim Baggot, page 290, that the entropy of an object is inversely proportional to its temperature. (He was describing the temperature of a black hole. Does this statement only apply to black holes?) No doubt he is correct, but wouldn't an increase of energy within an object give more possible states? Some molecules within a gas could have higher velocities. The gas might expand into a larger volume.
 
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  • #2
KurtLudwig said:
Please explain why in thermodynamics the entropy (disorder) of an object is inversely related to its temperature.

In general it's not/

KurtLudwig said:
Does this statement only apply to black holes?

It's certainly a leap from "it applies to black holes" to "it applies everywhere". It is probably true for any system with negative heat capacity.
 
  • #3
KurtLudwig said:
the entropy of an object is inversely proportional to its temperature

The entropy of the heat energy inside a rock is inversely proportional to the temperature of the rock. And proportional to the amount of the heat energy.

S = U/T

I wonder if we are allowed to say that the entropy of the heat energy inside a rock is inversely proportional to the temperature of the heat energy inside the rock? Like maybe the temperature T is the temperature of the heat energy U?
 
  • #4
Please explain negative heat capacity.
 
  • #5
KurtLudwig said:
Please explain negative heat capacity.

Do you understand heat capacity?
 
  • #6
KurtLudwig said:
wouldn't an increase of energy within an object give more possible states? Some molecules within a gas could have higher velocities. The gas might expand into a larger volume.

Let's say the object is a mixture of steam and liquid water at constant pressure. When we heat this object, its heat energy increases, its entropy increases, and its temperature stays constant. And that's because when one Joule of heat energy is added to that object, the object changes so that it has one Joule more potential energy. In this case there is no correlation between temperature and entropy.

What would happen if adding one Joule of heat energy to some object caused the object to have two Joules more potential energy? Well, when that object is heated, its heat energy increases, its entropy increases, and its temperature decreases. In this case there is a negative correlation between temperature and entropy.

And there are many cases when there is a positive correlation between entropy and temperature.
 
  • #7
If heat capacity ##C(T)## is a constant, entropy depends logarithmically on temperature. It's a result of integrating the infinitesimal definition

##\displaystyle dS=\frac{dQ}{T} = \frac{CdT}{T}##,

where there is the reciprocal ##T## proportionality. To get the entropy of something behave like ##S(T)\propto T^{-1}##, you'd have to set the function ##C(T)## just right for the integral to produce that result. What would it have to be?
 
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  • #8
hilbert2 said:
If heat capacity ##C(T)## is a constant, entropy depends logarithmically on temperature. It's a result of integrating the infinitesimal definition

##\displaystyle dS=\frac{dQ}{T} = \frac{CdT}{T}##,

where there is the reciprocal ##T## proportionality. To get the entropy of something behave like ##S(T)\propto T^{-1}##, you'd have to set the function ##C(T)## just right for the integral to produce that result. What would it have to be?

It would have to be ##C(T)\propto-T^-1##, right? In case the entropy is positive, this would mean the heat capacity needs to be negative.
 
  • #9
Livio Arshavin Leiva said:
It would have to be ##C(T)\propto-T^-1##, right? In case the entropy is positive, this would mean the heat capacity needs to be negative.

Yes, that's true and I don't think there is any material with that property.
 
  • #10
hilbert2 said:
Yes, that's true and I don't think there is any material with that property.

Every gravitationally bound system has this property.

It appears that the OP has lost interest, though.
 
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  • #11
Vanadium 50 said:
Every gravitationally bound system has this property.

Like a large cloud of point particle ideal gas that doesn't expand indefinitely because gravitation holds it together? I think there's the problem of having to set both temperature and density at the exact correct values for it to not collapse either, but I don't know much about GR.
 
  • #12
While PF likes to involke GR to solve inclined plane problems, it's not necessary in this case.

A cloud of gas in space loses energy and increases temperature as it collapses. Specific heat is negative.
 
  • #13
Physics is amazing! Thanks for your analyses.
 

1. Why does the entropy of an object decrease as its temperature increases?

The entropy of an object is a measure of the disorder or randomness of its molecules. As the temperature of an object increases, the molecules within it gain more kinetic energy and move around more rapidly. This increased movement leads to a more disordered state, resulting in a decrease in the object's entropy.

2. How does the relationship between entropy and temperature follow the laws of thermodynamics?

The second law of thermodynamics states that the total entropy of a closed system will always increase over time. This means that as the temperature of an object increases, its entropy must decrease in order to maintain the overall increase in entropy of the system. This inverse relationship between entropy and temperature is a fundamental principle of thermodynamics.

3. Can the entropy of an object ever reach zero?

No, it is impossible for the entropy of an object to reach zero. This is because even at absolute zero temperature (0 Kelvin), molecules still possess some inherent energy and will exhibit some level of disorder. Therefore, there will always be some degree of entropy present in any object.

4. How does the entropy of an object affect its ability to do work?

The decrease in entropy of an object at higher temperatures means that there is less energy available for the object to do work. This is because some of the energy is being used to increase the disorder of the molecules, rather than being available for useful work. Therefore, as the temperature of an object increases, its ability to do work decreases.

5. Does the relationship between entropy and temperature apply to all objects?

Yes, the relationship between entropy and temperature applies to all objects, regardless of their size, composition, or state (solid, liquid, gas). This is because it is a fundamental principle of thermodynamics and is based on the behavior of molecules at the atomic level.

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