- #1
member 428835
Hi PF!
Here equations 4 and 5 imply $$a^3=a_0^3+3 a_0 \Sigma \implies a_0 \approx a\left( 1- \frac{1}{a^2}\Sigma \right).$$ Can someone explain how this approximation is found?
Edit: I place in calculus thread because there must be some series expansion going on or a neglecting of terms.
Here equations 4 and 5 imply $$a^3=a_0^3+3 a_0 \Sigma \implies a_0 \approx a\left( 1- \frac{1}{a^2}\Sigma \right).$$ Can someone explain how this approximation is found?
Edit: I place in calculus thread because there must be some series expansion going on or a neglecting of terms.
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