- #1
JPanthon
- 20
- 0
Homework Statement
Suppose that δ = min{1,e/7}. Show that
if |x - 3| < δ, then |x^2 - 9| < e
Homework Equations
Don't know.
The Attempt at a Solution
|x - 3| |x + 3| < e
Given : |x - 3| < δ => |x - 3| < e/7
|x + 3| |x-3| < e/7
|x + 3| 7|x - 3| < e
Assume δ < 1, => |x - 3| < 1 => -4 < x < -2
Sub (-4)
| (-4) + 3| 7|x-3| < e
|x-3| < e/7
Is this circular? Please give some feedback!
Thank you!