Delta function and derivative of function wrt itself

In summary, the expression \frac{\partial f(x)}{\partial f(y)} =\delta(x-y) is a shorthand notation that follows the convention that it is equal to 1 if x=y and 0 if x\neq y. This convention expands the notion of "usually" and can be applied when integrating expressions involving the Dirac delta function. This result can be derived from the basic results \int_{-\infty}^{\infty}f(x)\delta{(x-y)}dx=f(y) and \int_{-\infty}^{\infty}f(y)\delta{(x-y)}dy=f(x). Additionally, in the special case of a functional F=F(f), the requirement \frac
  • #1
Trave11er
71
0
Can someone explain the following profound truth: [tex]\frac {\partial f(x)}{\partial f(y)} =\delta(x-y)[/tex]
 
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  • #2
The expression [itex]\dfrac{\partial f(x)}{\partial g(y)}[/itex] is really just a short-hand, but there are a handful of rules about which manipulations "usually work" with the short-hand. It turns out that the convention you've named---that [itex]\dfrac{\partial f(x)}{\partial f(y)}[/itex] is [itex]1[/itex] if [itex]x=y[/itex] and [itex]0[/itex] if [itex]x\neq y[/itex]---gives us a slightly broader notion of "usually".
 
  • #3
When you see the Dirac delta function in action, you ought to remind yourself:
"How will this look like when I integrate the expression?"

I haven't seen the result you post before, but do remember the two following results:
[tex]\int_{-\infty}^{\infty}f(x)\delta{(x-y)}dx=f(y)[/tex]
[tex]\int_{-\infty}^{\infty}f(y)\delta{(x-y)}dy=f(x)[/tex]
Most likely, your result follows from some clever manipulation of these two basic results.
 
  • #4
Thanks for the replies.
Have found the answer in Parr and Yang's book on Density Functional Theory:
For a functional F=F[f] have
[tex]\delta F = \int \frac {\delta F} {\delta f(y)} \delta f(y) \,dy[/tex]
In a special case that F=F(f), i.e. F is just some function of f it is required that:
[tex]\frac {\delta F(f(x))} {\delta f(y)} = \frac {dF}{df} \delta(x-y) [/tex] in order to have:
[tex] \delta F = \int \frac {\delta F} {\delta f(y)} \delta f(y) \,dx = \frac {dF} {df} \delta f(x) [/tex]
So that taking F = f, get:
[tex] \frac {\delta f(x)} {\delta f(y)} = \delta (x-y) [/tex]
 
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  • #5


The statement \frac {\partial f(x)}{\partial f(y)} =\delta(x-y) means that the derivative of a function f(x) with respect to itself evaluated at a point y is equal to the Dirac delta function evaluated at (x-y). This can be interpreted as the derivative of a function with respect to itself being a delta function, which is a mathematical representation of a point mass concentrated at a specific point. In other words, the derivative of a function with respect to itself is a very large value at the point of evaluation and zero everywhere else. This holds true for any function, making it a powerful and universal property in mathematics.
 

Related to Delta function and derivative of function wrt itself

1. What is the delta function?

The delta function, denoted by δ(x), is a mathematical function that is defined as 0 for all values of its argument except at x=0, where it is infinite. It is often used as a generalized function in mathematics and physics to represent a concentrated point of mass or charge.

2. How is the delta function related to the derivative of a function with respect to itself?

The delta function is closely related to the derivative of a function with respect to itself. In fact, the delta function can be defined as the derivative of the Heaviside step function with respect to itself. This means that the delta function is the "derivative" of a function that has a jump discontinuity at x=0.

3. What is the Laplace transform of the delta function?

The Laplace transform of the delta function is 1. This is because the Laplace transform of a function is defined as the integral of the function multiplied by e^(-st), where s is a complex variable. When s=0, the integral becomes the value of the function at t=0, which is 1 for the delta function.

4. How is the delta function used in solving differential equations?

The delta function is often used in solving differential equations with initial conditions. It can be used to represent a concentrated initial value at a specific point, allowing for the use of the Laplace transform to solve the differential equation.

5. Are there any practical applications of the delta function?

Yes, the delta function has many practical applications in mathematics and physics. It is commonly used in signal processing and image processing to represent a point source or impulse. It is also used in probability and statistics to model a point event with a probability of 1. Additionally, the delta function is used in quantum mechanics to represent a particle's position or momentum with infinite precision.

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