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loststudent123
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Homework Statement
A rule often used in shaft design states that the angle of twist shall not exceed 1° on a length equal to 20 diameters. What stress in the material does this imply if the modulus of rigidity is equal to 80 × 103 N/mm2 ?
Homework Equations
T/J=Gθ/L=τ/r
J=π?32(D^4-d^4)[/B]
G=shear stress/shear strain
shear stress=F/A
F=Wx9.81
The Attempt at a Solution
so i found that the length of the beam is D(20) letting D equal its diameter
so i got the equation
(80x10^3)/(D(20)=Wx9.81Xπ(D/2)/(D/2)
but I am not sure if that's right or how to solve when there is two unknowns?
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