Did I Misuse the Parallel Axis Theorem for Polar Moment of Inertia?

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The discussion centers on the application of the parallel axis theorem in calculating the polar moment of inertia. The textbook states the correct answer is J=330 cm^4, but the user struggled to identify the centroid's position relative to the given axes. It was clarified that the centroidal moment of inertia about the x-axis is 142.41 cm^4, which does not correspond to the axis as drawn in the figure. Additionally, the same reasoning applies to the moment of inertia about the y-axis, indicating that the parallel axis theorem should not be used for IYC. Proper understanding of the centroid's location is crucial for accurate calculations.
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Homework Statement
the centroidal moment of inertia about the x axis for the area shown is 142.41 cm^4. Most nearly what is the centroidal polar moment of inertia. The answer is C. What confuses me is that the solution says that the Y axis passes through the Centroid of the shape so parallel axis theorem shouldn't be applicable. Clarifications would be appreciated.
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Iyc= Iy + Ad^2
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The apparent correct answer given in the textbook is J=330 cm^4. I ended up using parallel axis theorem as I could not see how the Y axis passed through the centroid as the given y axis is completely towards the left side of the whole shape.My attempt at this question:-
 

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Usaid3112 said:
The apparent correct answer given in the textbook is J=330 cm^4. I ended up using parallel axis theorem as I could not see how the Y axis passed through the centroid as the given y axis is completely towards the left side of the whole shape.My attempt at this question:-
The centroidal moment of inertia "about the x-axis" is given to be IXC = 142.41 cm4. You can check that this is the moment of inertia about an axis parallel to the x-axis that passes through the centroid. So, it is not the moment of inertia about the x-axis as drawn in the figure.

The same applies to IYC. So, you would not use the parallel axis theorem in calculating IYC.

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