- #1
greg_rack
Gold Member
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- TL;DR Summary
- I get the practical difference between the two circuits, but can't really understand why
(Pictures below)
Circuit A(RC) Circuit B(RRC)
Hi guys, the thing I don't get is why the maximum charge of the A capacitor is ##q_{0}=C\cdot EMF## whilst in the other case you must consider the drop in tension caused by the first resistor, so the maximum charge of the cap is ##q_{0}=C\cdot (EMF-V_{R1})##.
Aren't the ends of the capacitor subject to the same potential difference in both cases? And since the charge is proportional to voltage and capacity, shouldn't it be the same in both cases?
Hi guys, the thing I don't get is why the maximum charge of the A capacitor is ##q_{0}=C\cdot EMF## whilst in the other case you must consider the drop in tension caused by the first resistor, so the maximum charge of the cap is ##q_{0}=C\cdot (EMF-V_{R1})##.
Aren't the ends of the capacitor subject to the same potential difference in both cases? And since the charge is proportional to voltage and capacity, shouldn't it be the same in both cases?