Diode operation from reverse bias to zero bias

In summary: The depletion region is enlarged because the electric field keeps the charge carriers in that region. Since the charge carriers are no longer confined to the depletion layer, they start moving around and eventually fall back to their original positions.
  • #1
CaptainMarvel1899
28
3
Assume we have a closed diode circuit .We connect the n type region of the diode to the positive terminal of the battery.We connect the p type region of the diode to the negative terminal of the battery.The depletion layer is increased.Now we open the circuit.Why the diode returns to its zero bias mode ?The lattice of silicon is more uniform and electrons have created bonds with unpaired electrons from Si atoms so they could not "return". What am I missing?
 
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  • #2
The depletion region is where charge is concentrated and it can increase or decrease in width depending on the applied voltage. The crystalline material atoms don't get displaced; just the charge gets displaced.
 
  • #3
dlgoff said:
The depletion region is where charge is concentrated and it can increase or decrease in width depending on the applied voltage. The crystalline material atoms don't get displaced; just the charge gets displaced.
Hmm I know that .I was just wondering how the covalent bonds between Si and B- can be broken so the diode would return to its unbiased state.
 
  • #4
Isn't a covalent bond one where there's a sharing of an electrons? Same answer as before.
 
  • #5
Yes it is.
 
  • #6
Once they form the covalent bond , how can they be free charge carriers again?
 
  • #7
CaptainMarvel1899 said:
What am I missing?
This part
Semiconductor crystals has something special between the 'pure' covalent bonds and metalic bonding. That's what makes them special. So the 'trapped' electrons/holes in the enlarged depletion layer are still mobile, their state is forcibly maintained just by the appropriate external electric field.
 
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  • #8
CaptainMarvel1899 said:
Assume we have a closed diode circuit .We connect the n type region of the diode to the positive terminal of the battery.We connect the p type region of the diode to the negative terminal of the battery.The depletion layer is increased.Now we open the circuit.Why the diode returns to its zero bias mode ?The lattice of silicon is more uniform and electrons have created bonds with unpaired electrons from Si atoms so they could not "return". What am I missing?

Leakage current does the discharging? Technically this is charge carrier drift due to the now comparatively large electric field.
 

What is a diode?

A diode is an electronic component that allows current to flow in only one direction. It consists of a semiconductor material with two terminals, an anode and a cathode.

How does a diode operate?

A diode operates by allowing current to flow from the anode to the cathode when it is forward biased, meaning the anode is at a higher voltage than the cathode. When reverse biased, with the cathode at a higher voltage, the diode blocks current from flowing.

What happens when a diode is in reverse bias?

When a diode is in reverse bias, it acts as an insulator and blocks current from flowing. This is because the majority carriers in the semiconductor material are pushed away from the junction, creating a depletion region that prevents current flow.

What is zero bias in diode operation?

Zero bias in diode operation refers to the state where the diode is not forward or reverse biased, meaning there is no external voltage applied across it. In this state, the diode will still have a small leakage current due to thermal energy.

What is the purpose of using a diode in reverse bias?

One purpose of using a diode in reverse bias is for protection against reverse voltage. By placing a diode in reverse bias across a circuit, it will prevent any reverse voltage from damaging the components. Another purpose is for signal modulation in electronic devices.

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