Engineering Dynamics homework — Does this cabinet sliding on the floor tip over?

AI Thread Summary
The discussion revolves around the dynamics of a cabinet tipping over when a force is applied. The user is confused about the signs of the moments calculated around point B, specifically regarding the "mad" term and its contribution to the overall moment balance. They note that the positive moment from the applied force and the negative moment from gravity should balance just before tipping occurs. The conversation explains that while horizontal acceleration exists, angular acceleration does not until the critical height is reached. Ultimately, at the tipping point, the forces on the cabinet's legs equalize, leading to a balance of moments.
Pipsqueakalchemist
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Homework Statement
I have the solutions and questions below
Relevant Equations
Sum of moment = (Moment of inertia)*(angular velocity)
So for this question, when using point B as the centre of the moment, I get different sign for the mad term. If you take clockwise as positive than 100N force and the force at point G are causing a positive moment and gravity is causing an negative moment. But the solutions have different signs as my attempt I don’t understand why. Appreciate it if someone can explain this to me.
 

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I understand part A just not part B
 
About the pivot point B, you have the positive moment of 100 N times maximum h plus the negative moment of 0.3 m times weight.
Both moments should be in balance just before the cabinet starts to tip over.
 
What I’m confused about is the sign of the mad term. The solution has it such that the mad causes a negative moment when you move the mad term to the left side of the equation. Shouldn’t it the mad term cause a positive moment about point B?
 
I may be wrong, but I believe that there should not be a mad term in that equation.
The horizontal net force (100 N - friction force) is the cause, while acceleration a is the effect.
Remove the 100 N force, and acceleration inmediately becomes negative (for the case of μ=0.25) or zero (for the case μ=0).

There is horizontal acceleration, but there is no angular acceleration while height h has not reached its critical value to make the cabinet tip over.

As the point of application of the 100 N force gets higher, the value of the horizontal net force that induces the horizontal acceleration remains the same.
Nevertheless, the positive moment induced by the 100 N force gradually increases until reaching the value of the negative moment induced by the weight of the cabinet which until that moment had kept some force on legs A because it had been greater than the positive moment.

Please, see:
http://mechanicsmap.psu.edu/websites/6_friction/slipping_vs_tipping/pdf/TippingVsSlipping_WorkedExample2.pdf

At the impending tipping moment, there is no more force on legs A while each leg B supports half of the cabinet's weight, and both moments about B cancel each other.
 
Last edited:
Hi,

I have responded on the other/new post of this question. Is this question different from the new thread? (seems like the same one, but maybe I am missing something)
 
It’s the same one, I just reposted it
 

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