Efficient Matrix Column Sum and Count: Solve Urgent Deadline in Hours

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The discussion revolves around a coding issue related to summing the elements of each column in a matrix and counting how many columns have a sum less than 1. The user initially provided a code snippet but encountered a compiler error indicating a missing semicolon. Clarification was sought on whether the variables `sum` and `count` were global or local and how they were initialized. It was confirmed that both are local and initialized to zero. The assignment required checking each column's sum and printing "OK" if all columns have sums less than 1. A suggested solution involved resetting `sum` to zero at the beginning of each column iteration, ensuring accurate calculations. The user faced challenges debugging in a Unix lab environment without copy/paste functionality, complicating error identification.
brad sue
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Hi,
Please I need help to do the following:

add the elements of each colunm of a matrix and
Count the number of colunm whose the sum is less than 1.

I did this: i is the indice of line , j =indice of colunm.. size = dimension of the square matrix.

for(j=0;j<size;j++)
{ for(i=0;i<size;i++)
{sum=sum+A[j];
if (sum<1)
count=count+1;}
}


The compiler says I am wrong . I have to turn this in few hours...
please help me!

Thanks
B
 
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What do you mean the compiler "says you are wrong"? Is it throwing a syntax error?

Is sum a global or local variable? How is it initialized? How about count?

Is the assignment to come up with one sum total for all columns, or one total per column?
 
berkeman said:
What do you mean the compiler "says you are wrong"? Is it throwing a syntax error?

Is sum a global or local variable? How is it initialized? How about count?

Is the assignment to come up with one sum total for all columns, or one total per column?

The compiler(Unix) say that a semicolon is missing after the second for loop. sum and count are a local variables.

In fact the assignemt says , "if the sum of each colunm ( for the whole matrix ) is less than 1 print "OK".

Example, if it is a 2 x 2 matrix,

0.2 0.25
0.3 .4

it should print "OK" since the sum of each colunm is less than 1.



This is why I use the count. if count = size ( size of the matrix) ,then each the colunm has a sum less than 1 , so I can print "OK".

sum and count are initialzed to zero at the beginning of the program.(sum=count=0;)

Thanks
 
You should probably post the whole code because if it is a syntax error it might have propagated from previous code. Sounds like it.
 
-Job- said:
You should probably post the whole code because if it is a syntax error it might have propagated from previous code. Sounds like it.
the problem is that I am working directly in unix lab . there is no copy/paste in the editor I am using..
 
the problem is that I am working directly in unix lab . there is no copy/paste in the editor I am using..
That's a problem with debugging then -- many errors are simple typos. When you retype it, you're likely to get it right that time, and thus we cannot catch your typo. :frown:
 
brad sue said:
the problem is that I am working directly in unix lab . there is no copy/paste in the editor I am using..
Then just pipe a listing to a file that you can post.
 
I am not sure if i have reached u in time
i think the syntax should be as follows

count=0;
for(j=0;j<size;j++)
{sum=0;
for(i=0;i<size;i++)
{sum=sum+A[j];}
if (sum<1)
count=count+1;}
 
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