Elastic Potential Energy and Hooke's Law Problem

In summary, the conversation is discussing a problem involving a small truck with a rear bumper that has a spring constant of 800,000 N/m. The bumper can be compressed up to 15cm without causing damage to the truck. The question is what is the maximum velocity with which a solid 1000-kg car can collide with the bumper without causing damage to the truck. The equations used are Kinetic Energy=(1/2)(m)(v^2) and Elastic Energy=(1/2)(k)(x^2), with the need to convert 15cm to 0.15m for the correct answer. However, the answer provided in the back of the book is incorrect as it assumes the bumper can move
  • #1
y201
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Homework Statement


A small truck is equipped with a rear bumper that has a spring constant of 800,000 N/m. the bumper can be compressed up to 15cm without causing damage to the truck. What is the maximum velocity with which a solid 1000-kg car can collide with the bumper without causing damage to the truck?


Homework Equations


Kinetic Energy=(1/2)(m)(v^2)
Elastic Energy=(1/2)(k)(x^2)


The Attempt at a Solution


I tried to make those two equations equal to one another and then isolate for "v" and solve for it. however, i got the wrong answer. the answer at the back of the book is 34 m/s. this problem is based on elastic potential energy and hooke's law. all help is appreciated.
 
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  • #2
Did you convert the 15cm to 0.15m? Otherwise the process you described is correct.

Actually, I just did the problem backwards. Using their "correct answer" of 34 m/s means the bumper must move 1.5 m, not 0.15. Basically the back of you book is wrong.
 
  • #3
thanks a lot birkeland for your help.
what did you get as the right answer?
 
  • #4
Birkeland said:
Did you convert the 15cm to 0.15m? Otherwise the process you described is correct.

Actually, I just did the problem backwards. Using their "correct answer" of 34 m/s means the bumper must move 1.5 m, not 0.15. Basically the back of you book is wrong.

what answer did you get using the 0.15m?
 
  • #5



To solve this problem, we can use the conservation of energy principle, which states that the total energy of a system remains constant. In this case, the initial kinetic energy of the car will be converted into elastic potential energy of the bumper at maximum compression, and then back into kinetic energy as the bumper pushes the car back.

We can set up the equation as follows:

Kinetic Energy of car = Elastic Potential Energy of bumper

(1/2)(m)(v^2) = (1/2)(k)(x^2)

Where m is the mass of the car (1000 kg), v is the maximum velocity of the car, k is the spring constant of the bumper (800,000 N/m), and x is the maximum compression of the bumper (15 cm = 0.15 m).

Solving for v, we get:

v = √[(kx^2)/m]

Substituting the values, we get:

v = √[(800,000 N/m)(0.15 m)^2 / 1000 kg] = 34 m/s

Therefore, the maximum velocity with which the car can collide with the bumper without causing damage to the truck is 34 m/s. This means that if the car is travelling at a speed higher than 34 m/s, it will cause damage to the truck's bumper.
 

Related to Elastic Potential Energy and Hooke's Law Problem

What is elastic potential energy?

Elastic potential energy is the potential energy stored in an elastic material when it is stretched or compressed. This energy is stored in the bonds between the molecules of the material and can be released when the material returns to its original shape.

What is Hooke's Law?

Hooke's Law is a principle that states the amount of force needed to stretch or compress an elastic material is directly proportional to the amount of stretch or compression. This means that as the material is stretched, the force applied to it increases in a linear manner.

What is the formula for elastic potential energy?

The formula for elastic potential energy is E=1/2kx^2, where E is the elastic potential energy, k is the spring constant, and x is the displacement from the equilibrium position.

How does Hooke's Law relate to elastic potential energy?

Hooke's Law and elastic potential energy are closely related because Hooke's Law helps us calculate the amount of force needed to stretch or compress an elastic material, which in turn allows us to determine the amount of elastic potential energy stored in the material.

What are some real-world applications of elastic potential energy and Hooke's Law?

Elastic potential energy and Hooke's Law have many applications in everyday life, such as in springs used in mattresses, trampolines, and car suspensions. They are also important in engineering and construction, where materials with elastic properties are used to absorb and release energy in various structures.

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