- #1
lys04
- 51
- 3
- Homework Statement
- Electric field near conducting shell
- Relevant Equations
- E=kQ/r^2
How would I do this question? I am having trouble figuring out what the radius is meant to be, why is it not 3R?
Induces a charge in the inner surface of the shell?PeroK said:The charge is inside a conducting shell. What is the relevance of that?
Have you studied that? Or, learned any techniques to find the electric field outside an asymmetric charge configuration?lys04 said:Induces a charge in the inner surface of the shell?
I've learnt Gauss's law, if that's applicable.PeroK said:Have you studied that? Or, learned any techniques to find the electric field outside an asymmetric charge configuration?
Gauss's law is useful. What can you say about the potential on the surface of a conductor?lys04 said:I've learnt Gauss's law, if that's applicable.
In a way: you will have to argue why the required symmetry (*) is present.lys04 said:I've learnt Gauss's law, if that's applicable.
It's uniform?PeroK said:Gauss's law is useful. What can you say about the potential on the surface of a conductor?
Yeah I'm not sure about thatBvU said:In a way: you will have to argue why the required symmetry (*) is present.
spherical symmetry of the field outside the shell
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Yes. The surface of the shell must be an equipotential. Now, the potential is fully determined by the boundary conditions (technically this is a uniqueness property of electrostatic solutions). You know that outside the shell a spherically symmetric potential is a solution, so it must be the only solution.lys04 said:It's uniform?
An electric field near a conducting shell refers to the distribution of electric charges around a conducting shell, which is a hollow metallic object. The electric field is created by the accumulation of charges on the surface of the conducting shell.
The electric field near a conducting shell can be calculated using the Gauss's Law, which states that the electric flux through a closed surface is equal to the total charge enclosed by that surface divided by the permittivity of free space.
The electric field near a conducting shell is directly proportional to the charge distribution on the surface of the shell. This means that as the charge on the shell increases, the electric field near the shell also increases.
The shape of a conducting shell does not affect the electric field near it. This is because the electric field is only dependent on the charge distribution on the surface of the shell, and not on the shape of the shell itself.
The electric field near a conducting shell has many practical applications. It is used in electrostatic shielding to protect sensitive electronic equipment from external electric fields. It is also used in electrostatic painting, where the electric field is used to attract paint particles to a conducting object. Additionally, the electric field near a conducting shell is important in the design of capacitors, which are used in many electronic devices.