MHB Elements of the form a/b in an integral domain - simple question

Math Amateur
Gold Member
MHB
Messages
3,920
Reaction score
48
In Alaca and Williams' (A&W) book: Introductory Algebraic Number Theory , Theorem 1.2.1 reads as follows:View attachment 3456Without any earlier definition or clarification, A&W refer to $$a/p$$ and $$b/p$$ (see text above) ... BUT ... how should we regard such elements? What exactly do they mean and how do we know they exist?

That is, is $$a/p$$ simply shorthand for an element $$x$$ where $$a = px$$?

Further, presumably using the notation $$a/p$$ implies that $$p^{-1}$$ exists ... BUT what if it does not exist?

Hope someone can clarify these apparently simple matters ...

Peter
 
Physics news on Phys.org
Peter said:
In Alaca and Williams' (A&W) book: Introductory Algebraic Number Theory , Theorem 1.2.1 reads as follows:View attachment 3456Without any earlier definition or clarification, A&W refer to $$a/p$$ and $$b/p$$ (see text above) ... BUT ... how should we regard such elements? What exactly do they mean and how do we know they exist?

That is, is $$a/p$$ simply shorthand for an element $$x$$ where $$a = px$$?

Further, presumably using the notation $$a/p$$ implies that $$p^{-1}$$ exists ... BUT what if it does not exist?

Hope someone can clarify these apparently simple matters ...

Peter

Since $D$ is an integral domain, and $p\neq 0$, there is a unique $c\in D$ such that $pc=a$ if $p|a$.

So when we write $a/p$, I think we mean $c$.
 
Back
Top