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Homework Statement
an elevator descends with a = 2m/s^2. there is a wedge on it. the wedge has an angle of 30 degrees. at the top of the incline of the wedge a small block is released with zero initial velocity from the elevator's frame of ref. after 1 sec, how much does the block travel along the incline of the wedge with respect to the wedge , given co-efficient of friction is 0.1 ?
Homework Equations
N = mgcos30, friction = co-efficient of friction x N
The Attempt at a Solution
the main problem I have is with the wording...does it mean that the elevator is going at g+2 m/s^2 or 2 m/s^2 ? I assumed the latter as the former would result in the wedge colliding with the top of the elevator.
what would happen in case A and case B ? would the results be different ?