Energy Considerations for a Block on a Spring and Incline

In summary, the problem involves a 200-g block pressed against a spring of force constant 1.40 kN/m, compressing the spring by 10.0 cm. The spring is located at the bottom of a ramp inclined at 60.0deg to the horizontal. Using energy considerations, the task is to determine the distance the block travels up the incline before stopping, with and without friction. When there is no friction, the initial potential energy of the block at the highest point is equal to the final kinetic energy of the compressed spring. The assumption is made that the initial kinetic energy of the block is zero. When there is friction, the energy stored in the spring is converted into potential and kinetic energy, and the
  • #1
jwxie
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Homework Statement



A 200-g block is pressed against a spring of force constant 1.40 kN/m until the block compresses the spring 10.0 cm. The spring rests at the bottom of the ramp inclined at 60.0deg to the horizontal.

Using energy considerations, determine how far up the incline the block moves before it stops (a) if there is no friction between the block and the ramp and (b) if the coefficient of kinetic friction is 0.400.

Homework Equations



Delta KE = Delta PE

The Attempt at a Solution



Okay, since the system is conservered with no fricition, I can assume that
initial energy = final energy, and we can rewrite it as
PE initial (of the block at the highest point) = KE final (of the spring as it gets compressed for 0.01 meter)

PE initial = KE final
X is the length the block travels from its original position
(mg*sin60 * X) = 1/2 * k * (0.01m^2)

And then I was wondering why do we assume that the initial KE of the block is zero? The problem did not state that there was no initial velocity for the block.
 
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  • #2
Energy store in the spring is
E = 1/2*k*x^2.
When the block detaches from the spring, stored energy in the spring in converted into PE and KE. The PE is m*g*x*sinθ, where x is the compression of the spring.
Now you get the initial velocity. final velocity is zero. Find the distance traveled by the block along the ramp.
 
  • #3
hi, thanks. i was so dump did not consider its reverse condition.
thanks!
 

Related to Energy Considerations for a Block on a Spring and Incline

1. What is the "Spring/ramp energy problem"?

The spring/ramp energy problem is a physics problem that involves calculating the potential and kinetic energies of an object on a ramp that is connected to a spring. It is often used to illustrate the conservation of energy principle.

2. How do you calculate the potential energy in a spring/ramp energy problem?

To calculate the potential energy in a spring/ramp energy problem, you need to know the mass of the object, the gravitational acceleration, and the height of the ramp. The formula for potential energy is PE = mgh, where m is the mass, g is the gravitational acceleration, and h is the height.

3. What is the formula for calculating the kinetic energy in a spring/ramp energy problem?

The formula for calculating the kinetic energy in a spring/ramp energy problem is KE = 1/2mv^2, where m is the mass and v is the velocity of the object. This formula represents the energy of an object in motion.

4. How does the spring affect the energy in a spring/ramp energy problem?

In a spring/ramp energy problem, the spring provides potential energy to the object as it compresses or expands. This potential energy is then converted into kinetic energy as the object moves down the ramp. The spring's stiffness and the distance it is compressed or expanded determine the amount of potential energy it provides.

5. What is the purpose of the spring/ramp energy problem in physics?

The purpose of the spring/ramp energy problem in physics is to illustrate the conservation of energy principle. This principle states that energy cannot be created or destroyed, only transferred from one form to another. In this problem, the potential energy from the spring is converted into kinetic energy as the object moves down the ramp, and the total energy remains constant throughout the process.

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